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Dvinal [7]
2 years ago
15

The diameter of a circle measures 7 5/6 inches. What is the radius of the circle? Enter your answer as a mixed number in the box

.
Mathematics
1 answer:
andrew-mc [135]2 years ago
4 0

The radius of the circle expressed as a mixed number is:  3\frac{11}{12} inches.

<h3>What is the Radius of a Circle?</h3>

Radius of a circle = half the measure of the diameter of a circle.

Given:

diameter of a circle = 7\frac{5}{6} inches

Therefore:

Radius of the circle = 1/2(7\frac{5}{6})

= 1/2(47/6)

= (1 × 47)/(2 × 6)

= 47/12

= 3\frac{11}{12} inches.

Therefore, the radius of the circle expressed as a mixed number is:  3\frac{11}{12} inches.

Learn more about radius of a circle on:

brainly.com/question/24375372

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Help please!!!
katovenus [111]

Answer:

x = \frac{7+\sqrt{47}\times i }{4}

Step-by-step explanation:

<u>To solve quadratic systems,we always substitute one variable in terms if the other and then solve the equation.</u>

x + 2y = 6                                 ---------------(1)

y - 5 = (x-2)^{2}         ---------------(2)

y = (x-2)^{2} + 5         ---------------(3)

Substitute (3) in (1) ,

x + 2( (x-2)^{2} + 5 ) = 6

(a + b)^{2} =a^{2} + 2ab + b^{2}

x + 2( x^{2} - 4x + 4 + 5 ) = 6

2x^{2} - 7x + 12=0      --------------(4)

The roots of the quadratic equation ax^{2}  +bx+c is

x = \frac{(-b) + \sqrt{(-b)^{2}-4 \times ac }  }{2 \times a}  -----------(5)

According to equation (5),solution of (4) is

x =  \frac{7 + \sqrt{(-7)^{2}-4 \times 24 }  }{2 \times 2}

x =  \frac{7+\sqrt{49-96}}{4}

x = \frac{7+\sqrt{47}\times i }{4}

 

4 0
3 years ago
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