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2 years ago

7

Justin is on a road trip. Over the past 2 days, he has driven a total distance of 715 miles at an average speed of 65 miles per

hour. If
Justin drove 2 hours today, how many hours did he drive yesterday?

1 answer:

julia-pushkina [17]2 years ago

7 0

Answer:

1 hour did he drive yesterday

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Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

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Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

So

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is:

$P(C) = (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7\\\\P(C) = \frac{1}{729}$

D. The probability is $\frac{1}{729}$ . This number is quite close to zero. Therefore it is an unlikely bastate event.

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Answer:

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3 years ago

Andre draws a tape diagram for 3÷2/3

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Answer:

No I do not agree with Andre says that 3 divided by 2/3 Solving for 3 ÷ 2/3

3 ÷ 2/3

= 3 × 3/2

= 9/2

= 4 1/2

Therefore, 3 divided by 2/3 is 4 1/2

Andre's reasoning is wrong.

Step-by-step explanation:

It is incorrect

Let's divide and compare the sum

3 : 2/3 = 3*3/2 = 9/2 = 4 1/2

and

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The 1/3 fraction is 1/2 of 2/3 fraction so instead of counting 1/3 as 1/3 it should be counted as 1/2

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