Answer: f(x) = 3x^(2)-2x+1
f(x) = 3x^(2)-2x+1 = y-intercept (0, 1).
g(x) = -10x^(2)+50x = y-intercept (0, 0).
As we see, the first equation (f(x) = 3x^(2)-2x+1) has a y-intercept of (0, 1), while the other equation (g(x) = -10x^(2)+50x) has a y-intercept of (0, 0). This means that the quadratic equation that has the greatest y-intercept is f(x) = 3x^(2)-2x+1, which is (0, 1).
Step-by-step explanation:
Hope this helps =)
Answer:
A) -1
Step-by-step explanation:
anything raised to the zero power is 1 but if there is a negative without parentheses around it then it becomes -1
ex, (-4)° = 1
Answer:
D ( If a < b, then b < a ) is false
Step-by-step explanation:
If b is greater than a then a cannot be greater than b making it false
20,000/10=2,000 :)
Good luck