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2 years ago

If a number is divisible by 2 and 3, why is it also divisible by 6?

2 answers:

8 0

2 and 3 are prime numbers. So they are prime factors of any number. Therefore if any number is divisible by 2 & 3 both then it will be divisible by 6.

Arada [10]2 years ago

3 0

Answer:

They have 6 when multiplying it

Step-by-step explanation:

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I don't know how to do this!!

saw5 [17]

3x-1=77 (due to exterior alternate angle)
Or, 3x=77-1
or, 3x=76
or, x=76/3
or, x=25.3

6 0

3 years ago

Please help me this is for a grade

IgorC [24]

Answer:

Step-by-step explanation:

4 0

3 years ago

Please help and show all work so I can fully understand it, thanks.

seraphim [82]

Answer:

$\frac{1}{m-4}$

Step-by-step explanation:

$\frac{\frac{4m-5}{m^4 -7m^3 +12m^2}}{\frac{4m-5}{m^3 -3m^2}}$

Factor the equation:

$\frac{\frac{4m-5}{m^2(m^2 -7m+12)}}{\frac{4m-5}{m^2(m-3)}}$

$\frac{\frac{4m-5}{m^2(m-3)(m-4)}}{\frac{4m-5}{m^2(m-3)}}$

Rewrite to suit the format of multiplying two fractions. Remember, dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second. A reciprocal of a fraction is when one switches the place of the numerator and the denominator, that is, the value on top (numerator), and the value on the bottom (denominator).

$\frac{4m-5}{m^2(m-3)(m-4)}*\frac{m^2(m-3)}{4m-5}$

Simplify, take out common terms that are found on both the numerator and denominator

$\frac{4m-5}{m^2(m-3)(m-4)}*\frac{m^2(m-3)}{4m-5}$

$\frac{1}{m-4}$

4 0

3 years ago

Write 0.5% as a decimal.

Pavlova-9 [17]

0.5% = 0.005
0.5% = 1/200

6 0

3 years ago

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Two angles are supplementary. The first angle measures 40 degrees. What is the measurement of the second angle

Dmitrij [34]

Supplementary angles add up to 180º
If one is 40º, then the other is (180º-40º) = 140º

None of those choices describes a plane.
choice C is the only example of a plane.

8 0

4 years ago

Read 2 more answers