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Kisachek [45]
2 years ago
13

Use the drop-down menu to complete each statement. according to this graph, at $10 the quantity supplied is about . as the price

of the good rises, the quantity supplied will .
Mathematics
1 answer:
ANTONII [103]2 years ago
3 0

Answer:

14

increase

Step-by-step explanation:

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PLZ HELP ME I WILL GIVE BRAINLIEST....
guapka [62]

Answer:

A. 2, 3, and 4

B: 4

Step-by-step explanation:

4 0
3 years ago
What is the interquartile range for the data set? 241, 230, 201, 245, 209, 211, 242, 201, 204, 228, 242, 243 Enter your answer i
creativ13 [48]
The answer is 36. The formula for IQR is Q3-Q1. 

Q3=242.5    Q1=206.5

242.5-206.5=36

So 36 is your IQR
8 0
4 years ago
Read 2 more answers
fred thinks of a number that is greater than 110 and less than 120. he can make his number with same number of hundreds,tens and
VashaNatasha [74]

The number Fred thinks of is 111

<em><u>Solution:</u></em>

Given that, Fred thinks of a number that is greater than 110 and less than 120

He can make his number with same number of hundreds,tens and ones

<em><u>To find: Fred's number</u></em>

Given that the number is greater than 110 and less than 120

The possible numbers are:

111 , 112, 113, 114, 115, 116, 117, 118, 119

But he can make his number with same number of hundreds,tens and ones

So the numbers in ones, tens and hundreds place are same

So the only possible number is 111

Thus the number Fred thinks of is 111

8 0
4 years ago
A suspension footbridge has two 2-meter vertical supports 20 meters apart. The lowest point of the cable connecting them is 1 me
maw [93]

Answer:

y = (x - 10)^2 / 100 + 1

Step-by-step explanation:

given:


A suspension footbridge has two 2-meter vertical supports 20 meters apart so the cable connecting 'em will be a convex parabola


The lowest point of the cable, which is the vertex, 1 meter above the path.


y-axis represents the left support and the other vertical support is at x=20


by symmetry, the vertex is mid-pt between the two supports, @ x=20/2=10

so vertex is at (10,1)

vertex form of parabola is y = a(x - h)^2 + k, where (h, k) is the vertex

so y = a(x-10)^2 + 1

at y-axis, x=0, y=2

2 = a(0-10)^2 + 1

2 - 1 = 100a

a = 1/100

so the eqn is y = (x - 10)^2 / 100 + 1

7 0
3 years ago
Read 2 more answers
Simplify 7 square root of 3 end root minus 4 square root of 6 end root plus square root of 48 end root minus square root of 54
Katen [24]
7\sqrt3-4\sqrt6+\sqrt{48}-\sqrt{54}\\\\=7\sqrt3-4\sqrt6+\sqrt{16\cdot3}-\sqrt{9\cdot6}\\\\=7\sqrt3-4\sqrt6+\sqrt{16}\cdot\sqrt3-\sqrt9\cdot\sqrt6\\\\=7\sqrt3-4\sqrt6+4\sqrt3-3\sqrt6\\\\=\boxed{11\sqrt3-7\sqrt6}
3 0
3 years ago
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