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kumpel [21]
1 year ago
8

A quantity with an initial value of 3700 decays exponentially at a rate of 6% every 5

Mathematics
1 answer:
SSSSS [86.1K]1 year ago
4 0

Answer:

2369.86

Step-by-step explanation:

f(36)=3700(1−0.06) ^36/5

2369.857704098921

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3 0
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Read 2 more answers
If f'(x)=2/x and f(sqrt(e))=5, then f(e)=
docker41 [41]
f'(x)=\dfrac2x
\implies f(x)=\displaystyle\frac2x\,\mathrm dx=2\ln|x|+C

f(\sqrt e)=5\implies 5=2\ln|\sqrt e|+C
\implies 5=\dfrac22\ln e+C
\implies C=4
\implies f(x)=2\ln|x|+4
\implies f(e)=2\ln|e|+4=6
3 0
3 years ago
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