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Maksim231197 [3]
2 years ago
11

What is the factored form of x2 – x – 2? (x – 2)(x 1) (x 2)(x 1) (x – 2)(x – 1) (x 2)(x – 1)

Mathematics
1 answer:
Alexxx [7]2 years ago
8 0

A quadratic equation is an equation whose leading coefficient is of the second degree. The factored form of the quadratic equation x²-x-2 is (x+1)(x-2).

<h3>What is a quadratic equation?</h3>

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers.

It is written in the form of ax²+bx+c.

The factored form of the quadratic equation can be done in the following manner,

x^2-x-2\\\\= x^2-2x+x-2\\\\=x(x-2)+(x-2)\\\\=(x+1)(x-2)

Thus, the factored form of the quadratic equation x²-x-2 is (x+1)(x-2).

Learn more about Quadratic Equations:

brainly.com/question/2263981

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Of the following options, what could be a possible first step in solving the equation -7x -5= x + 3
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You would need to add 7x to both sides.
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angle-angle similarity theorem

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Which figure is the image produced by applying the composition t 0,3 r 0,90 to figure R?
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Option A is correct

The only figure after composition of t_{0 , 3} (r_{0,90^{\circ}}) to figure R is Figure H

Step-by-step explanation:

From the given figure in R;

The coordinates in Figure R ;

(1 , -1) , (2, -2) ,(4, -2) ( 0, -4)

Composite function defined as when one function is substituted into another function.

To Apply the composition t_{0 , 3} (r_{0,90^{\circ}}) to figure R;

First apply the Reflection r_{0, 90^{\circ}} in Figure R;

The rule of reflection is given by:

(x,y) \rightarrow (-y,x)

By applying the rule of reflection in Figure R ,

then, the coordinates becomes;

(1 , -1) \rightarrow (1, 1)

(2 , -2) \rightarrow (2, 2)

(4 , -2) \rightarrow (2, 4)

(0, -4) \rightarrow (4, 0)

Now, apply the translation t_{0,3}

Translation : It is a type of transformation that moves each point in a figure the same distance in the same direction.

then,

the rule of translation is:

(x,y) \rightarrow (x+0,y+3)

Apply the rule of translation on coordinates (1,1) , (2,2),  (2,4) and (4,0)

then

(1 , 1) \rightarrow (1+0 1+3) =(1,4)

(2, 2) \rightarrow (2+0 2+3) =(2, 5)

(2, 4) \rightarrow (2+0 4+3) =(2 ,7) and

(4, 0) \rightarrow (4+0 0+3) =(4 ,3)

Then, the only figure after composition of t_{0 , 3} (r_{0,90^{\circ}}) to figure R is Figure H





7 0
4 years ago
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