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olga55 [171]
2 years ago
10

How many different nth roots does a nonzero complex number have?

SAT
1 answer:
Reika [66]2 years ago
6 0

The Complex nth Roots Theorem with any nonzero complex number has exactly n ∈ N distinct nth roots.  

<h3>What is a non-zero complex number?</h3>

This is the quantity which does not equal zero is said to be nonzero. A real nonzero number must be either positive or negative, and a complex nonzero number can have either real or imaginary part nonzero.

The roots lie on a circle of radius centered at the origin and spaced out evenly by angles of 2π/n.

Learn more about the <em>nth root</em> here:

brainly.com/question/1581238

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*SAT QUESTION*
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Answer and Explanation:

Greetings!

Let's~answer~your~question!

Triangle~ ABC ~is ~a ~right~ triangle~ with ~its~ right~ angle ~at ~B. ~Therefore,~AC\\is~ the~ hypotenuse~ of~ right~ triangle~ ABC,~ and~ AB ~and ~BC ~are~ the~ legs~ of~ right~\\ triangle ~ABC.

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Since ~triangle~DEF~is ~similar~ to~ triangle~ ABC,~ with~ vertex ~F ~corresponding~to~ vertex~ C,~ the~ measure\\ of~angle~ \angle F~equals~ the~ measure~ of~ angle~\angle C.

Therefore,~ sinF=sinC. ~From ~the~ side~ lengths~ of ~triangle~ ABC,

sinF=\frac{opposite ~side}{hypotenuse} =\frac{AB}{AC} =\frac{12}{20}=\frac{3}{5}

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