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Sladkaya [172]
2 years ago
5

Which of the following best explains how algorithms that run on a computer can be used to solve problems?

Computers and Technology
1 answer:
timama [110]2 years ago
7 0

The statement which best explains how algorithms running on a computer can be used to solve problems is; D. Some problems cannot be solved by an algorithm.

<h3>What is an algorithm?</h3>

An algorithm is simply a standard formula or procedures which is made up of a set of finite steps and instructions that must be executed on a computer, so as to proffer solutions to a problem or solve a problem under appropriate conditions.

However, it should be noted that it is not all problems that can be solved by an algorithm, especially because the required parameters and appropriate conditions are not feasible or met.

Read more on algorithm here: brainly.com/question/24793921

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Explanation:

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   print()

Kindly check the code output below.

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#include<stdio.h>

#include<stdlib.h>

int comment1(FILE *fp)

{

   char ch;

   int count=0;

   while(fscanf(fp,"%c",&ch)!=EOF)

   {

       if(ch=='\n')

       {

           return count;

       }

       count++;

   }

   return count;

}

int comment2(FILE *fp)

{

   char ch;

   int count=0;

   while(fscanf(fp,"%c",&ch)!=EOF)

   {

       if(ch=='*')

       {

           fscanf(fp,"%c",&ch);

           if(ch=='/')

           {

               return count;

           }

           count++;

       }

       count++;

   }

   return 0;

}

int main()

{

   printf("Enter the file name:");

   char s[1000],ch,ch1;

   scanf("%s",s);

   FILE*fp;

   fp = fopen(s,"r");

   int count=0;

   while(fscanf(fp,"%c",&ch)!=EOF)

   {

       if(ch=='\"')

       {

           while(fscanf(fp,"%c",&ch)!=EOF)

           {

               if(ch=='\"')

               {

                   break;

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               {

                   fscanf(fp,"%c",&ch);

               }

           }

       }

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       {

           fscanf(fp,"%c",&ch);

           if(ch=='/')

           {

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   }

   printf("%d\n",count);

   return 0;    

}

3 0
3 years ago
Read 2 more answers
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