A.

1 answer:

4 0

Using exponential function concepts, it is found that the student error is in the subtraction of the day rate, as he forgot to subtract from 100% = 1.

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

$A(t) = A(0)(1 - r)^t$

In which:

A(0) is the initial value.

r is the decay rate, as a decimal.

In this problem, the initial value of the computer is of A(0) = 1500, while it decays at a rate of 15% a year, hence r = 0.15 and the equation is:

$A(t) = A(0)(1 - r)^t$

$A(t) = 1500(0.85)^t$

Or equivalently, as a sequence:

$a_n = 1500(0.85)^{n-1}$

Hence, it is found that the student error is in the subtraction of the day rate, as he forgot to subtract from 100% = 1.

More can be learned about exponential function concepts at brainly.com/question/25537936

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S=n(a1+an)/2 gives the partial sum of an arithmetic sequence. What is the formula solved for an?

Veseljchak [2.6K]

S = n(a1 + an)/2
2S = n(a1 + an)
2S = na1 + nan
nan = 2S - na1
an = (2S - n a1)/n

6 0

3 years ago

Read 2 more answers

Pls help me!! I just need help on both of the following questions, a-d on each

Ymorist [56]

I'll do a and e on the first one to show you how to do it

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So 6 × 3 = 18 ; but since there is a negative on the 3 your answer will be -18

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same for this; 20 ÷ 5 = 4, but since the 20 is negative the answer will be -4

You do b, c, d, and f on the first question. Tell me what you get and we'll go from there

Now for the second question 

I will do a and d to show you how to do this then you do the rest (I'm inserting a picture with these)

a. $4(-2 \frac{1}{3}) + 7 \frac{1}{6}$
First go ahead and turn the fractions into improper fractions, this makes them a bit easier to work with. When multiplying fractions; they do not need a common denominator, all you do is multiply top by top and bottom by bottom.
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3 years ago

Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi

ziro4ka [17]

Answer:

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(5.75241,0.06281)$