The slope of the line is -23
<h3>How to determine the
slope of the
line?</h3>
The line’s equation is given in point-slope form:
y − 6 = (−23)(x + 6)
The line’s equation in point-slope is represented as:
y − y1 = m(x - x1)
Where
m represents the slope
By comparing y − y1 = m(x - x1) and y − 6 = (−23)(x + 6), we have
m = -23
Hence. the slope of the line is -23
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-7x + 6y =5
x intercept. y=0
-7(x) + 6(0)=5
x=-5/7
y intercept, x=0
-7(0)+6(y) =5
y=5/6
Answer:
The answer is 3
Step-by-step explanation:
Because 4x6=24
2x2x2=8
24 divided by 8=3
Hope this helped and have a great day!
Check the picture below, so the parabola looks more or less like so, with a vertex at (0 , -7), let's recall the vertex is half-way between the focus point and the directrix.
so this horizontal parabola opens up to the left-hand-side, meaning that the "P" distance is a negative value.
![\textit{horizontal parabola vertex form with focus point distance} \\\\ 4p(x- h)=(y- k)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h+p,k)}\qquad \stackrel{directrix}{x=h-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\supset}\qquad \stackrel{"p"~is~positive}{op ens~\subset} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Ctextit%7Bhorizontal%20parabola%20vertex%20form%20with%20focus%20point%20distance%7D%20%5C%5C%5C%5C%204p%28x-%20h%29%3D%28y-%20k%29%5E2%20%5Cqquad%20%5Cbegin%7Bcases%7D%20%5Cstackrel%7Bvertex%7D%7B%28h%2Ck%29%7D%5Cqquad%20%5Cstackrel%7Bfocus~point%7D%7B%28h%2Bp%2Ck%29%7D%5Cqquad%20%5Cstackrel%7Bdirectrix%7D%7Bx%3Dh-p%7D%5C%5C%5C%5C%20p%3D%5Ctextit%7Bdistance%20from%20vertex%20to%20%7D%5C%5C%20%5Cqquad%20%5Ctextit%7B%20focus%20or%20directrix%7D%5C%5C%5C%5C%20%5Cstackrel%7B%22p%22~is~negative%7D%7Bop%20ens~%5Csupset%7D%5Cqquad%20%5Cstackrel%7B%22p%22~is~positive%7D%7Bop%20ens~%5Csubset%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
![\begin{cases} h=0\\ k=-7\\ p=-9 \end{cases}\implies 4(-9)(x-0)~~ = ~~[y-(-7)]^2 \\\\\\ -36x=(y+7)^2\implies x=-\cfrac{1}{36}(y+7)^2](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D%20h%3D0%5C%5C%20k%3D-7%5C%5C%20p%3D-9%20%5Cend%7Bcases%7D%5Cimplies%204%28-9%29%28x-0%29~~%20%3D%20~~%5By-%28-7%29%5D%5E2%20%5C%5C%5C%5C%5C%5C%20-36x%3D%28y%2B7%29%5E2%5Cimplies%20x%3D-%5Ccfrac%7B1%7D%7B36%7D%28y%2B7%29%5E2)
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