Round to the nearest hundreth

Rus_ich [418]

The given equation is in point-slope form.

The general form of an equation in point slope form is:

$y- y_{1}=m(x- x_{1})$

Here m is the slope and $x_{1}$ and $y_{1}$ are the coordinates of the point.

So in given equation the slope is 2/3, and the coordinates of point are (1,3)

8 0

3 years ago

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En la tienda de mascotas "Animalo-T", se desea elevar un elefante de 2,900 kg utilizando una elevadora hidráulica de plato grand

Korvikt [17]

Answer:

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

Step-by-step explanation:

Por el Principio de Pascal se conoce que el esfuerzo experimentado por el elefante es igual a la presión ejercida por el plato pequeño. Es decir:

$\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}}$ (1)

Donde:

$F_{1}$ - Fuerza experimentada por el elefante, medida en newtons.

$F_{2}$ - Fuerza aplicada sobre el plato pequeño, medida en newtons.

$A_{1}$ - Área del plato grande, medida en metros cuadrados.

$A_{2}$ - Área del plato pequeño, medida en metros cuadrados.

La fuerza aplicada sobre el plato pequeño es:

$F_{2} = \left(\frac{A_{2}}{A_{1}} \right)\cdot F_{1}$

La fuerza experimentada por el elefante es su propio peso. Por otra parte, el área del plato es directamente proporcional al cuadrado de su diámetro. Es decir:

$F_{2} = \left(\frac{D_{2}}{D_{1}} \right)^{2}\cdot m\cdot g$ (2)

Donde:

$D_{1}$ - Diámetro del plato grande, medido en centímetros.

$D_{2}$ - Diámetro del plato pequeño, medido en centímetros.

$m$ - Masa del elefante, medida en kilogramos.

$g$ - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que $D_{1} = 0.75\,m$ , $D_{2} = 0.13\,m$ , $m = 2900\,kg$ y $g = 9.807\,\frac{m}{s^{2}}$ , entonces la fuerza a aplicar al émbolo pequeño es:

$F_{2} = \left(\frac{0.13\,m}{0.75\,m} \right)^{2}\cdot (2900\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$F_{2} = 854.473\,N$

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

3 0

3 years ago

a rectangle swimming pool is 4 ft deep. one side of the pool is 2.5 times longer than the other. the amount of water needed to f

mojhsa [17]

Find the are of the pool by dividing the volume by the depth:

1960 / 4 = 490

The pool is 490 square feet.

Area is found by multiplying the length by the width.

Let the width = X

We are told the length is 2.5X ( 2.5 times longer)

So we now have 2.5x * x = 490

2.5x * x = 2.5x^2

Now we have 2.5x^2 = 490

Divide both sides by 2.5:

x^2 = 490/2.5

x^2 = 196

find X by taking the square root of 196:

x = √196

x = 14

The width is 14 feet

The length is 2.5 * 14 = 35 feet

8 0

3 years ago

Devin used what he learned in clas to determine that for every 8 grams of oxygen in water, there is 1 gram of hydrogen

MAXImum [283]

And?... is that the question or is there more?

6 0

3 years ago

What is the difference between rates and proportions???

frez [133]

A rate often involves time: e. g., 33 feet per second; also, we are finding the ratio of one type of measurement with respect to another: distance and time.

A proportion is often the ratio of different measures of the same thing:

e. g. 5 apples
------------
7 apples

6 0

4 years ago