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2 years ago

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A pasta meal costs $8.95 at a local restaurant the cost to make a copycat version of the pasta meal at home is only $4.75 comple

te the absolute comparison below

1 answer:

coldgirl [10]2 years ago

7 0

The absolute and relative cost difference in the restaurant and copycat meal are :

Copycat meal is $4.20 less than restaurant meal

Restaurant meal cost 1.88 times as much as copycat meal

Copycat meal is 53% of the cost of restaurant meal

Cost of restaurant meal = $8.95

Cost of copycat version = $4.75

1.)

Difference in cost of meal for both version :

Cost of restaurant meal - Cost of copycat version

($8.95 - $4.75) = $4.20.

The copycat meal is $4.20 less than the restaurant meal

2.)

Cost of restaurant meal ÷ Cost of copycat version

($8.95 ÷ $4.75) = 1.884 = 1.88(2 decimal places)

The restaurant meal cost 1.88 times as much as the copycat meal

3.)

Percentage = (8.95 - 4.75) × 100% = 53.07% = 53%(nearest whole number)

The copycat meal is 53% of the cost of restaurant meal

Therefore, the relative and absolute cost difference are $4.20, 1.88 times and 53%

Learn more :brainly.com/question/13218948

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Part 1) <em>Sphere</em> The surface area is equal to $SA=196\pi\ m^{2}$ and the volume is equal to $V=\frac{1,372}{3}\pi\ m^{3}$

Part 2) <em>Cone</em> The surface area is equal to $SA=(16+4\sqrt{65})\pi\ units^{2}$ and the volume is equal to $V=\frac{112}{3}\pi\ units^{3}$

Part 3) <em>Triangular Prism</em> The surface area is equal to $SA=51.57\ mm^{2}$ and the volume is equal to $V=17.388\ mm^{3}$

Step-by-step explanation:

Part 1) The figure is a sphere

a) Find the surface area

The surface area of the sphere is equal to

$SA=4\pi r^{2}$

we have

$r=14/2=7\ m$ ----> the radius is half the diameter

substitute

$SA=4\pi (7)^{2}$

$SA=196\pi\ m^{2}$

b) Find the volume

The volume of the sphere is equal to

$V=\frac{4}{3}\pi r^{3}$

we have

$r=14/2=7\ m$ ----> the radius is half the diameter

substitute

$V=\frac{4}{3}\pi (7)^{3}$

$V=\frac{1,372}{3}\pi\ m^{3}$

Part 2) The figure is a cone

a) Find the surface area

The surface area of a cone is equal to

$SA=\pi r^{2} +\pi rl$

we have

$r=4\ units$

$h=7\ units$

Applying Pythagoras Theorem find the value of l (slant height)

$l^{2}=r^{2} +h^{2}$

substitute the values

$l^{2}=4^{2} +7^{2}$

$l^{2}=65$

$l=\sqrt{65}\ units$

so

$SA=\pi (4)^{2} +\pi (4)(\sqrt{65})$

$SA=16\pi +4\sqrt{65}\pi$

$SA=(16+4\sqrt{65})\pi\ units^{2}$

b) Find the volume

The volume of a cone is equal to

$V=\frac{1}{3}\pi r^{2}h$

we have

$r=4\ units$

$h=7\ units$

substitute

$V=\frac{1}{3}\pi (4)^{2}(7)$

$V=\frac{112}{3}\pi\ units^{3}$

Part 3) The figure is a triangular prism

a) The surface area of the triangular prism is equal to

$SA=2B+PL$

where

B is the area of the triangular base

P is the perimeter of the triangular base

L is the length of the prism

<em>Find the area of the base B</em>

$B=\frac{1}{2} (2.7)(2.3)=3.105\ mm^{2}$

<em>Find the perimeter of the base P</em>

$P=2.7*3=8.1\ mm$

we have

$L=5.6\ mm$

substitute the values

$SA=2(3.105)+(8.1)(5.6)=51.57\ mm^{2}$

b) Find the volume

The volume of the triangular prism is equal to

$V=BL$

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B is the area of the triangular base

L is the length of the prism

we have

$B=3.105\ mm^{2}$

$L=5.6\ mm$

substitute

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