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Slav-nsk [51]
2 years ago
9

You and another lifeguard find an unresponsive adult on the locker room floor. The other lifeguard goes to summon ems personnel.

You form an initial impression, complete a primary assessment and find that the victim has a pulse but is not breathing. Which of the following should you do next?
SAT
1 answer:
Naddik [55]2 years ago
7 0

Given what we know, we can confirm that the next step to take is to give ventilations to assist the patient in breathing until EMS arrives.

<h3>What are ventilations?</h3>

Ventilation is a form of assisted breathing. This is often done through the use of machines but can be achieved through manual means as well when necessary, such as in this situation. The lifeguard will give ventilation once every 5 or so seconds to bring the patient's breathing rate to a steady 12 times per minute until EMS arrives.

Therefore, we can confirm that the next step to take is to give ventilations at a rate of 12 times per minute to assist the patient in breathing steadily until EMS arrives.

To learn more about ventilation visit:

brainly.com/question/2624209?referrer=searchResults

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A student is bouncing on a trampoline. At her highest point, her feet are 95 cm above the trampoline. When she lands, the trampo
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The time she spent in contact with the trampoline is 0.1619 seconds.

The objective of this question is to determine for how long she is in contact with the trampoline?

The conservational force is exerted on the trampoline is equivalent to the sum of the potential energy at the highest point and the elastic energy at the lowest point.

∴

From the given information;

\mathbf{mg \dfrac{(95 +25)}{100} = \dfrac{1}{2}k ( \dfrac{25}{100})^2}

\mathbf{m\times g\times 1.2 = k(0.03125)}

\mathbf{m\times 9.8 \times 1.2 = k(0.03125)}

\mathbf{\dfrac{m}{k} = \dfrac{(0.03125)}{9.8 \times 1.2}}

\mathbf{\dfrac{m}{k} = 0.002657}

Using the Simple Harmonic Motion to determine the time at which she is in contact with the trampoline, we have;

\mathbf{t= \dfrac{T}{2}}

\mathbf{t= \dfrac{2 \pi}{2} \sqrt{\dfrac{m}{k}}}

where;

  • \mathbf{\dfrac{m}{k} = 0.002657}

\mathbf{t= \dfrac{2 \pi}{2} \times \sqrt{0.002657}}}

\mathbf{t=0.1619\ sec}}

Learn more about the time period of a Simple Harmonic Motion here:

brainly.com/question/17315536

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