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sweet-ann [11.9K]
2 years ago
15

Does anyone know the answer and how to get the answer ?

Mathematics
1 answer:
My name is Ann [436]2 years ago
8 0

Answer:

3. 384\ square\ inches

Step-by-step explanation:

To solve this, find the areas of the smaller geometric shapes and add them together.

1. Rectangle (top)

A_1 = lw = 20 * 5 = 100

2. Rectangle (middle)

A_2 = lw = 20 * 8 = 160

3. Rectangle (bottom)

A_3 = lw = 20 * 5 = 100

4. Triangle (left)

A_4 = \frac{bh}{2} = \frac{8*3}{2} = \frac{24}{2} = 12

4. Triangle (right)

A_5 = \frac{bh}{2} = \frac{8*3}{2} = \frac{24}{2} = 12

Add the areas together for the total surface area.

A_t = 100 + 160 + 100 + 12 + 12 = 384

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8m^3 - 28m^2 + 6m - 21. You solve by factoring by grouping!!! quick please
Leya [2.2K]

Answer:

(2m - 7)(4 {m}^{2}  + 3)

Step-by-step explanation:

8m^3 - 28m^2 + 6m - 21 \\  = 4 {m}^{2} (2 {m}  - 7) + 3(2m - 7) \\  = (2m - 7)(4 {m}^{2}  + 3)

4 0
3 years ago
3) Let h(x)= |2x|-4. Find h(x) when x = -7.<br> a) -10<br> b) 10<br> c) -13<br> d) 13
svlad2 [7]

Answer:

h(x) = 10

Step-by-step explanation:

Given

h(x) = |2x| - 4

x = -7

Find h(x)

Substitute -7 for x

h(x) = |2*-7| - 4

h(x) = |-14| - 4

Absolute values return positive. So:

h(x) = 14 - 4

h(x) = 10

8 0
3 years ago
Determine the equation of the line that goes through points (1.1) and (3.7).
ValentinkaMS [17]

Answer:

The equation of the line that goes through points (1,1) and (3,7) is \mathbf{y=3x-2}

Step-by-step explanation:

Determine the equation of the line that goes through points (1,1) and (3,7)

We can write the equation of line in slope-intercept form y=mx+b where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

We have x_1=1, y_1=1, x_2=3, y_2=7

Putting values and finding slope

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{7-1}{3-1}\\Slope=\frac{6}{2}\\Slope=3

We get Slope = 3

Finding y-intercept

y-intercept can be found using point (1,1) and slope m = 3

y=mx+b\\1=3(1)+b\\1=3+b\\b=1-3\\b=-2

We get y-intercept b = -2

So, equation of line having slope m=3 and y-intercept b = -2 is:

y=mx+b\\y=3x-2

The equation of the line that goes through points (1,1) and (3,7) is \mathbf{y=3x-2}

4 0
3 years ago
I need help on number 36
Ahat [919]
What do you need help with? it helps us to know the question!
8 0
4 years ago
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