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Tamiku [17]
3 years ago
6

Being technologically literate requires being able to ______. a. use advanced graphics manipulation tools (adobe photoshop) b. u

se the most common operating systems (windows and apple os) c. adjust network settings for a company lan d. none of the above please select the best answer from the choices provided a b c d
Computers and Technology
1 answer:
Vilka [71]3 years ago
3 0

Being technologically literate requires being able to use the most common operating systems (windows and apple). That is option B.

<h3>What are operating systems?</h3>

The operating systems are important software of a computer system which manages the computer's memory and other application software.

Examples of common operating systems include:

  • Apple operating system and

  • windows operating system

These operating systems are regularly updated by the technological companies that produced them. Therefore, being technologically literate requires being able to use the most common operating systems.

Learn more about  Operating System here:

brainly.com/question/22811693

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5.23 LAB: Contains the character
torisob [31]

Answer:

In C++:

#include<iostream>

#include<vector>

using namespace std;

int main() {

int len;

cout<<"Length: ";  cin>>len;

string inpt;

vector<string> vect;

for(int i =0;i<len;i++){

  cin>>inpt;

  vect.push_back(inpt); }

char ch;

cout<<"Input char: ";  cin>>ch;  

for(int i =0;i<len;i++){

  size_t found = vect.at(i).find(ch);  

      if (found != string::npos){

          cout<<vect.at(i)<<" ";

          i++;

      }

}  

return 0;

}

Explanation:

This declares the length of vector as integer

int len;

This prompts the user for length

cout<<"Length: ";  cin>>len;

This declares input as string

string inpt;

This declares string vector

vector<string> vect;

The following iteration gets input into the vector

for(int i =0;i<len;i++){

  cin>>inpt;

  vect.push_back(inpt); }

This declares ch as character

char ch;

This prompts the user for character

cout<<"Input char: ";  cin>>ch;  

The following iterates through the vector

for(int i =0;i<len;i++){

This checks if vector element contains the character

  size_t found = vect.at(i).find(ch);  

If found:

      if (found != string::npos){

Print out the vector element

          cout<<vect.at(i)<<" ";

And move to the next vector element

          i++;

      }

}  

7 0
2 years ago
A computer is a multipurpose device that accepts input processes data and produces output all according to a series of stored
yulyashka [42]
According to a series of stored procedures 
8 0
3 years ago
Create a program that displays a menu to select addition, subtraction, or multiplication. Using random numbers between 0 and 12
Lemur [1.5K]

Answer:

This question is answered using C++

#include<iostream>

#include <cstdlib>

#include <ctime>

using namespace std;

int main(){

   int ope, yourresult;

   cout<<"Select Operator: \n"<<"1 for addition\n"<<"2 for subtraction\n"<<"3 for multiplication\n";

   cout<<"Operator: ";

   cin>>ope;

   srand((unsigned) time(0));

   int num1 = rand() % 12;

   int num2 = rand() % 12;

   int result = 1;

   if(ope == 1){

       cout<<num1<<" + "<<num2<<" = ";

       result = num1 + num2;

   }

   else if(ope == 2){

       cout<<num1<<" - "<<num2<<" = ";

       result = num1 - num2;

   }

   else if(ope == 3){

       cout<<num1<<" * "<<num2<<" = ";

       result = num1 * num2;

   }

   else{

       cout<<"Invalid Operator";

   }

   cin>>yourresult;

   if(yourresult == result){

       cout<<"Correct!";

   }

   else{

       cout<<"Incorrect!";

   }

   return 0;

}

Explanation:

This line declares operator (ope) and user result (yourresult) as integer

   int ope, yourresult;

This prints the menu

   cout<<"Select Operator: \n"<<"1 for addition\n"<<"2 for subtraction\n"<<"3 for multiplication\n";

This prompts the user for operator

   cout<<"Operator: ";

This gets user input for operator

   cin>>ope;

This lets the program generates different random numbers

   srand((unsigned) time(0));

This generates the first random number

   int num1 = rand() % 12;

This generates the second random number

   int num2 = rand() % 12;

This initializes result to 1

   int result = 1;

If the operator selected is 1 (i.e. addition), this prints an addition operation and calculates the actual result

<em>    if(ope == 1){</em>

<em>        cout<<num1<<" + "<<num2<<" = ";</em>

<em>        result = num1 + num2;</em>

<em>    }</em>

If the operator selected is 2 (i.e. subtraction), this prints an subtracttion operation and calculates the actual result

<em>    else if(ope == 2){</em>

<em>        cout<<num1<<" - "<<num2<<" = ";</em>

<em>        result = num1 - num2;</em>

<em>    }</em>

If the operator selected is 3 (i.e. multiplication), this prints an multiplication operation and calculates the actual result

<em>    else if(ope == 3){</em>

<em>        cout<<num1<<" * "<<num2<<" = ";</em>

<em>        result = num1 * num2;</em>

<em>    }</em>

If selected operator is not 1, 2 or 3, the program prints an invalid operator selector

<em>    else{</em>

<em>        cout<<"Invalid Operator";</em>

<em>    }</em>

This gets user input

   cin>>yourresult;

This checks if user result is correct and prints "Correct!"

   if(yourresult == result){

       cout<<"Correct!";

   }

If otherwise, the program prints "Incorrect!"

<em>    else{</em>

<em>        cout<<"Incorrect!";</em>

<em>    }</em>

   return 0;

6 0
3 years ago
I don't have a split screen in my Samsung Galaxy A02 why???​
weqwewe [10]

Answer:

YOU CAN open

Turn on Multi Window

1. Select the Recent apps key. 2. Select the desired app icon, then select Open in split screen view.

Explanation:

PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT

6 0
2 years ago
Calculate the cash used to retire debt for each of the six months. Since the company can't pay down more debt than there is cash
BabaBlast [244]

Answer:

The required cash used to retire a debt can be computed as follows:

Cash used to retire debt = cash available to retire a debt, if the cash available to retire debt is less than the loan balance from previous month. Otherwise, cash used to retire debt is equal to the loan balance from previous month.

The excel formula to perform this task is provided as follows:

D33 = IF(D32<C34,D32,C34)

The same formula is used to get the values for E33 to I33.

Explanation:

See the attached picture for table.

5 0
3 years ago
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