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Finger [1]
3 years ago
15

Find all complex solutions of x^2+5x-5=0.

Mathematics
1 answer:
kykrilka [37]3 years ago
6 0
We use quadratic formula for that one
remember that √-1=i

so

for
ax^2+bx+c=0
x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}
so
given
1x^2+5x-5=0
a=1
b=5
c=-5

x=\frac{-5+/-\sqrt{5^2-4(1)(-5)}}{2(1)}
x=\frac{-5+/-\sqrt{25+20}}{2}
x=\frac{-5+/-\sqrt{45}}{2}
x=\frac{-5+/-3\sqrt{5}}{2}

solutions:
x=\frac{-5+3\sqrt{5}}{2}, \frac{-5-3\sqrt{5}}{2}
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