Question

Find all complex solutions of x^2+5x-5=0.

Answer 1

We use quadratic formula for that one
remember that √-1=i

so

for
ax^2+bx+c=0
$x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$
so
given
1x^2+5x-5=0
a=1
b=5
c=-5

$x=\frac{-5+/-\sqrt{5^2-4(1)(-5)}}{2(1)}$
$x=\frac{-5+/-\sqrt{25+20}}{2}$
$x=\frac{-5+/-\sqrt{45}}{2}$
$x=\frac{-5+/-3\sqrt{5}}{2}$

solutions:
$x=\frac{-5+3\sqrt{5}}{2}, \frac{-5-3\sqrt{5}}{2}$