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MrRa [10]
3 years ago
7

The perimeter of rectangle is 48ft the length is 16 from. Whats is the area?

Mathematics
1 answer:
solniwko [45]3 years ago
7 0

Answer:

128

Step-by-step explanation:

There are 2 lengths, 16 x 2 = 32. 48 - 32 = 16. 16 divded by 2 equals 8. 8 x 16 = 128.

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Find the area of the following shape. You must show all work to receive credit.
djverab [1.8K]

Answer:

54

Step-by-step explanation:

This can be divided into triangle ABF and trapezoid BCDE.

A = A₁ + A₂

A = ½ (10) (3) + ½ (6 + 7) (6)

A = 15 + 39

A = 54

The area is 54 square units.

8 0
3 years ago
Read 2 more answers
Evaluate the expression when x = -6<br> x with the power of 2 7x -5
miss Akunina [59]

answer:

-167

Step-by-step explanation:

if x=-6 you use the equation with -6 for x, 27 times -6 is -162, -162-5 is -167.

4 0
3 years ago
In the drawing above two rugby players start 41 meters apart at rest. Player 1 accelerates at 2.2 m/s^2 and player 2 accelerates
Anettt [7]

Answer:

The time that elapses before the players collide is 4.59 secs

Step-by-step explanation:

The distance between the two players is 41 meters. Hence, they would have total distance of 41 meters by the time they collide.

We can write that

S₁ + S₂ = 41 m

Where S₁ is the distance covered by Player 1 before collision

and S₂ is the distance covered by Player 2 before collision

From one of the equations of kinematics for linear motion,

S = ut + \frac{1}{2} at^{2}

Where S is distance

u is the initial velocity

a is acceleration

and t is time

Since the players collide at the same time, then time spent by player 1 before collision equals time spent by player 2 before collision

That is, t₁ = t₂ = t

Where t₁ is the time spent by player 1

and t₂ is the time spent by player 2

For player 1

S = S₁

u = 0 m/s ( The player starts at rest)

a = 2.2 m/s²

Then,

S₁ = 0(t) + \frac{1}{2} (2.2)t^{2}

S₁ = 1.1t^{2}

t^{2} = \frac{S_{1} }{1.1}

For player 2

S = S₂

u = 0 m/s ( The player starts at rest)

a = 1.7 m/s²

Then,

S₂ = 0(t) + \frac{1}{2} (1.7)t^{2}

S₂ = 0.85t^{2}

t^{2} = \frac{S_{2} }{0.85}

Since the time spent by both players is equal, We can  write that

t^{2} = t^{2}

Then,

\frac{S_{1} }{1.1} =  \frac{S_{2} }{0.85}

0.85S_{1} = 1.1S_{2}

From, S₁ + S₂ = 41 m

S₂ = 41  - S₁

Then,

0.85S_{1} = 1.1 ( 41 -S_{1} )

0.85S_{1} = 45.1 - 1.1S_{1}

0.85S_{1} + 1.1S_{1} = 45.1 \\1.95S_{1} = 45.1\\S_{1} = \frac{45.1}{1.95} \\S_{1}  = 23.13 m

This is the distance covered by the first player. We can then put this value into t^{2} = \frac{S_{1} }{1.1} to determine how much time elapses before the players collide.

t^{2} = \frac{S_{1} }{1.1}

t^{2} = \frac{23.13 }{1.1}

t^{2} = 21.03\\t = \sqrt{21.03} \\t = 4.59 secs

Hence, the time that elapses before the players collide is 4.59 secs

3 0
4 years ago
Can someone help PLZ
Rom4ik [11]

Answer:

the height is 20

formula

V=ABh

3

Step-by-step explanation:

6 0
3 years ago
-8/3 divided by -2/6 simplify
Luba_88 [7]

To divide a fraction by a fraction, multiply the first fraction by the reciprocal of the second one. That means, keep the first fraction the way it is. Change the division to a multiplication. Flip the second fraction.

-8/3 / -2/6 = -8/3 * -6/2 = (8 * 6)/(3 * 2) = 8

5 0
3 years ago
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