Lets solve the question,
Given dimensions are:
Length = 26 feet
Width = 14 feet
concrete walkway with width = c
After installing the concrete walkway dimensions of the walkway will be,
Length = 26 + 2c
Width = 14 + 2c
She wants to build a wooden deck around the pool with a concrete walkway of width = w
Thus the dimensions of the wooden deck around the pool will be,
Length = 
Width = 
Now the perimeter of the wooden deck will be,
Perimeter = 2(length + width)
![= 2[(26 +2c + 2w) + 2(14 + 2c + 2w)] = 2(40 + 4c + 4w) = (80 + 8c + 8w)](https://tex.z-dn.net/?f=%3D%202%5B%2826%20%2B2c%20%2B%202w%29%20%2B%202%2814%20%2B%202c%20%2B%202w%29%5D%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%3D%202%2840%20%2B%204c%20%2B%204w%29%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%3D%20%2880%20%2B%208c%20%2B%208w%29)
Therefore, perimeter of the wooden deck would be: 80 + 8c + 8w
Perimeter = (80 + 8c + 8w)
Learn more about Perimeter on:
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Answer:
Step-by-step explanation:
From the picture attached,
Addition of the blocks in first row is 60
a + a + a + 12 = 60
3a + 12 = 60
3a = 60 - 12
3a = 48
a = 16
For second row,
(b + 5) + (b + 5) + (b + 5) + (b + 5) = 60
4(b + 5) = 60
b + 5 = 15
b = 10
For third row,
(a + b) + c = (b + 5) + (b + 5) + (b + 5)
a + b + c = 3(b + 5)
16 + 10 + c = 3(10 + 5) [Since, a = 16 and b = 10}
26 + c = 45
c = 45 - 26
c = 19
For fourth row,
3c + d = 60
3(19) + d = 60
57 + d = 60
d = 60 - 57
d = 3
Answer: 6-3x=18
Step-by-step explanation: You just have to read what the question says for example Six less than three times a number is 6-3x=18
It would be 7x10^-2
That number would be rounded to 0.07
