All categories

4 years ago

How many different combinations are possible if a coin is tossed five times?

Mathematics

2 answers:

aivan3 [116]4 years ago

8 0

2 heads and tails. time 5 times is 10. so 10 combos

Andrei [34K]4 years ago

5 0

The answer would indeed be 10 combos if you were to toss a coin 5 times.

You might be interested in

DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD. If the area of the parallelogram is 1470 cm2 ,

STatiana [176]

Answer:

BM = 30 cm, DL = 42 cm

Step-by-step explanation:

The area of the parallelogram = 1470 cm², AB = 35 cm, AD = 49 cm, DL and BM are the heights on sides AB and AD.

area of the parallelogram = base × height = AD × height of AD = AD × BM

⇒ 1470 cm² = 49 cm × BM

BM = 1470 cm² / 49 cm = 30 cm

BM = 30 cm

Also:

area of the parallelogram = base × height = AB × height of AB = AB × DL

⇒ 1470 cm² = 35 cm × DL

DL = 1470 cm² / 35 cm = 42 cm

DL = 42 cm

3 0

3 years ago

What time is 98 hours after 10:00 in the morning?

Rzqust [24]

11:00 AM.

Hope I helped.

3 0

3 years ago

Read 2 more answers

Solve (x + 2<5) U (X - 7 > -6). {x 1-6 {x|x<3 or x > 1) {x 1 x < 0]

Andreas93 [3]

I need a graph or something to show beside the numbers

7 0

3 years ago

The percentage of the dam released during the flood

Dennis_Churaev [7]

Answer: what is the question?

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Evaluate the following integral (Calculus 2) Please show step by step explanation!

Nuetrik [128]

Answer:

$4\ln \left| \dfrac{1}{3}\sqrt{9+(\ln x)^2} + \dfrac{1}{3}\ln x \right|+\text{C}$

Step-by-step explanation:

Fundamental Theorem of Calculus

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

$\displaystyle \int \dfrac{4}{x\sqrt{9+(\ln(x))^2}}\:\:\text{d}x$

Rewrite 9 as 3²:

$\implies \displaystyle \int \dfrac{4}{x\sqrt{3^2+(\ln(x))^2}}\:\:\text{d}x$

Integration by substitution

$\boxed{\textsf{For }\sqrt{a^2+x^2} \textsf{ use the substitution }x=a \tan\theta}$

$\textsf{Let } \ln x=3 \tan \theta$

$\begin{aligned}\implies \sqrt{3^2+(\ln x)^2} & =\sqrt{3^2+(3 \tan\theta)^2}\\ & = \sqrt{9+9\tan^2 \theta}\\ & = \sqrt{9(1+\tan^2 \theta)}\\ & = \sqrt{9\sec^2 \theta}\\ & = 3 \sec\theta\end{aligned}$

Find the derivative of ln x and rewrite it so that dx is on its own:

$\implies \ln x=3 \tan \theta$

$\implies \dfrac{1}{x}\dfrac{\text{d}x}{\text{d}\theta}=3 \sec^2\theta$

$\implies \text{d}x=3x \sec^2\theta\:\:\text{d}\theta$

Substitute everything into the original integral:

$\begin{aligned} \implies \displaystyle \int \dfrac{4}{x\sqrt{9+(\ln(x))^2}}\:\:\text{d}x & = \int \dfrac{4}{3x \sec \theta} \cdot 3x \sec^2\theta\:\:\text{d}\theta\\\\ & = \int 4 \sec \theta \:\: \text{d}\theta\end{aligned}$

Take out the constant:

$\implies \displaystyle 4 \int \sec \theta\:\:\text{d}\theta$

$\boxed{\begin{minipage}{7 cm}\underline{Integrating $\sec kx$}\\\\$\displaystyle \int \sec kx\:\text{d}x=\dfrac{1}{k} \ln \left| \sec kx + \tan kx \right|\:\:(+\text{C})$\end{minipage}}$