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2 years ago

Pre-calc/Trig Suppose that θ=arcsin(4/6). What is cos(2θ)? (round to 4 decimals)

Mathematics

1 answer:

mixer [17]2 years ago

4 0

Answer:

0.7453

Step-by-step explanation:

$arcsin( \frac{4}{6} ) = 0.7297 \\ cos(0.7297) = 0.7453$

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Solve the inequality for x. Show each step of the solution.<br> 16x > 12(2x – 6) – 24

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You want to start this problem by handling the parentheses and distributing the 12.
So 16x > 12(2x - 6) - 24 would become...
So 16x > 24x - 72 - 24
Next you would combine like terms...
So 16x > 24x - 96
Then to get rid of the negative you would add 96 to both sides...
So 16x + 96 > 24x
After that you would subtract 16x from both sides...
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3 years ago

Read 2 more answers

Which of the quadratic functions has the narrowest graph?

charle [14.2K]

Answer:

$y=\frac{1}{8}x^2$

Step-by-step explanation:

A quadratic function has the formula ax² + bx + c

To determine if a graph will be narrow or wide, the leading coefficient, a, will be the factor that determines this
The greater the coefficient, the narrower the parabola
The lesser the coefficient, the wider the parabola

Here all of the functions are in the form ax²

In $y=\frac{1}{8}x^{2}$ , our "a" term is $\frac{1}{8}$
In y = -2x², our "a" term is -2
In y = -3x², our "a" term is -3
In $y=\frac{1}{3}x^{2}$ , our "a" term is $\frac{1}{3}$

We can eliminate the two functions with the negative coefficients because they are much smaller than the two functions with the fractions as coefficients, and will therefore open much wider.

We can now compare the two remaining functions, $y=\frac{1}{8}x^2$ and $y=\frac{1}{3}x^2$

Giving the two fractions common denominators would turn them into $y = \frac{3}{24}x^2$ and $y=\frac{8}{24} x^2$
The equation with the larger fraction will be the parabola that is the narrowest. In this case, it is the $y=\frac{8}{24} x^2$ .
Therefore, $y=\frac{1}{8}x^2$ will have the narrowest graph

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3 years ago