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2 years ago

A series of drawn pictures (like a comic) of key visual shots of planned production for video is a/an

Computers and Technology

1 answer:

Ne4ueva [31]2 years ago

4 0

Answer:

The correct answer is <u>D) Storyboard</u>

Explanation:

A storyboard is used during the initial planning stage of filmmaking. You draw pictures to demonstrate the general idea of what shots you want to get before actually going out and filming on a set/studio.

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Write a C program that reads two hexadecimal values from the keyboard and then stores the two values into two variables of type

sattari [20]

Solution :

#include $$$$

//Converts $\text{hex string}$ to binary string.

$\text{char}$ * hexadecimal $\text{To}$ Binary(char* hexdec)

{

long $\text{int i}$ = 0;

char *string = $(\text{char}^ *) \ \text{malloc}$ (sizeof(char) * 9);

while (hexdec[i]) {

//Simply assign binary string for each hex char.

switch (hexdec[i]) {

$\text{case '0'}:$

strcat(string, "0000");

break;

$\text{case '1'}:$

strcat(string, "0001");

break;

$\text{case '2'}:$

strcat(string, "0010");

break;

$\text{case '3'}:$

strcat(string, "0011");

break;

$\text{case '4'}:$

strcat(string, "0100");

break;

$\text{case '5'}:$

strcat(string, "0101");

break;

$\text{case '6'}:$

strcat(string, "0110");

break;

$\text{case '7'}:$

strcat(string, "0111");

break;

$\text{case '8'}:$

strcat(string, "1000");

break;

$\text{case '9'}:$

strcat(string, "1001");

break;

case 'A':

case 'a':

strcat(string, "1010");

break;

case 'B':

case 'b':

strcat(string, "1011");

break;

case 'C':

case 'c':

strcat(string, "1100");

break;

case 'D':

case 'd':

strcat(string, "1101");

break;

case 'E':

case 'e':

strcat(string, "1110");

break;

case 'F':

case 'f':

strcat(string, "1111");

break;

default:

printf("\nInvalid hexadecimal digit %c",

hexdec[i]);

string="-1" ;

}

i++;

}

return string;

}

int main()

{ //Take 2 strings

char *str1 =hexadecimalToBinary("FA") ;

char *str2 =hexadecimalToBinary("12") ;

//Input 2 numbers p and n.

int p,n;

scanf("%d",&p);

scanf("%d",&n);

//keep j as length of str2

int j=strlen(str2),i;

//Now replace n digits after p of str1

for(i=0;i<n;i++){

str1[p+i]=str2[j-1-i];

}

//Now, i have used c library strtol

long ans = strtol(str1, NULL, 2);

//print result.

printf("%lx",ans);

return 0;

}

4 0

2 years ago

Sharon is thinking about opening a bakery. She knows she wants to set her own hours, reduce her stress and make a profit. But sh

kondaur [170]

C would not be a beginner move.

hope it helps

6 0

3 years ago

. A Worker in Microworkers can also be an Employe

bija089 [108]

Answer:

A Worker in Microworkers can also be an Employer: After reaching $25 in earnings. After placing an initial deposit of $10, and launching a valid campaign. If success rate is maintained at 75% before launching a campaign. After creating a separate Employer account.

Explanation:

6 0

2 years ago

What was the name of the first computer (machine) language?

Angelina_Jolie [31]

In 1957, the first of the major languages appeared in the form of FORTRAN. Its name stands for FORmula TRANslating system. The language was designed at IBM for scientific computing. The components were very simple, and provided the programmer with low-level access to the computers innards.

8 0

3 years ago

Read 2 more answers

A Function checkMe takes three parameters, a character and two integers. If the sum of the two integers is negative, and the cha

Paul [167]

Answer:

Check the explanation

Explanation:

Here is the program with function definition and two sample calls.

Code:

#include <iostream>

using namespace std;

//checkMe FUNCTION which takes values a, b and c

void checkMe(char &a, int &b, int &c)

{

//if sum of b and c is negative and a is 'n', b and c are set to 0, otherwise a is set to 'p'

if((b+c)<0 && a=='n')

{

b = 0;

c = 0;

}

else

{

a = 'p';

}

int main()

{

//first test case when else part is executed

char a = 'n';

int b = 5;

int c = 6;

checkMe(a, b, c);

cout<<a<<" "<<b<<" "<<c<<endl;

//second test case when if part is executed

a = 'n';

b = -4;

c = -5;

checkMe(a, b, c);

cout<<a<<" "<<b<<" "<<c<<endl;

return 0;

}

Kindly check the Output below:

7 0

3 years ago