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2 years ago

Here is Diya's work writing the expression 6 - 2x + 5 + 4x with fewer terms. Describe the mistake that Diya made.

Mathematics

1 answer:

Rom4ik [11]2 years ago

3 0

Answer:

Below.

Step-by-step explanation:

This is the correct solution:

6 - 2x + 5 + 4x

= -2x + 4x + 6 + 5

= 2x + 11.

It looks like they added unlike terms together (4x + 5) to give 9x (incorrect) then added the 4x to give 13x.

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Graph 9x+6y=-12 please

sasho [114]

Answer:

Attached

Step-by-step explanation:

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3 years ago

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kiruha [24]

For this case we have the following expression:

$\frac {216 ^ {n-2}} {(\frac {1} {36}) ^ {3n}} = 216$

We multiply both sides by: $(\frac {1} {36}) ^ {3n}$

$216 ^ {n-2} = 216 * (\frac {1} {36}) ^ {3n}$

We divide both sides by 216:

$\frac {216 ^ {n-2}} {216} = (\frac {1} {36}) ^ {3n}$

To divide powers of the same base, we place the same base and subtract the exponents:

$216 ^ {n-2-1} = (\frac {1} {36}) ^ {3n}\\216 ^ {n-3} = (\frac {1} {36}) ^ {3n}$

Rewriting:

$(6 ^ 3) ^ {n-3} = (\frac {1} {6 ^ 2}) ^ {3n}\\6 ^ {3n-9} = \frac {1} {6 ^ {6n}}\\6^{ 3n-9} * 6^{ 6n} = 1$

To multiply powers of the same base, we place the same base and add the exponents:

$6^{ 3n-9 + 6n} = 1\\6^{ 9n-9} = 1$

We know that any number raised to zero is 1, $a ^ 0 = 1.$

So, for equality to be true:

$9n-9 = 0\\9n = 9\\n = \frac {9} {9}\\n = 1$

Answer:

$n = 1$

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3 years ago

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