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Eduardwww [97]
2 years ago
6

Rewrite the function by completing the square. f(x)=x^2-4x-26

Mathematics
1 answer:
Radda [10]2 years ago
5 0

Answer:

(x-2)^2-30

Step-by-step explanation:

use the form ax^2+bx+c to find the values of a, b, and c.

a=1, b= -4, c = -26

consider the vertex form of a parabola

a(x+d)^2+e

substitute the values of a and b into the formula d=\frac{b}{2a}

d=\frac{4}{2(1)}

simplify the right side.

find the value of e using the formula e=c-\frac{b^2}{4a}

e=30

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LA plane is trying to travel 250 miles at a bearing of 20° E of S, however, it ends 230 miles away from the
Semmy [17]

Answer:

The wind pushed the plane 65.01 miles in the direction of 45.56 ^{\circ} East of North  with respect to the destination point.

Step-by-step explanation:

Let origin, O, br the starting point and point D be the destination at 250 miles at a bearing of 20° E of S, but due to wind let D' be the actual position of the plane at 230 miles away from the  starting point in the direction of 35° E of South as shown in the figure.

So, we have |OD|=250 miles and |OD'|=230 miles.

Vector \overrightarrow{DD'} is the displacement vector of the plane pushed by the wind.

From figure, the magnitude of the required displacement vector is

|DD'|=\sqrt{|AB|^2+|PQ|^2}\;\cdots(i)

and the direction is \alpha east of north as shown in the figure,

\tan \alpha=\frac{|PQ|}{|AB|}\;\cdots(ii)

From the figure,

|AB|=|OA-OB|

\Rightarrow |AB|=|OD\cos 20 ^{\circ}-OD'\cos 35 ^{\circ}|

\Rightarrow |AB|=|250\cos 20 ^{\circ}-230\cos 35 ^{\circ}|

\Rightarrow |AB|=45.52 miles

Again, |PQ|=|OP-OQ|

\Rightarrow |PQ|=|OD\sin 20 ^{\circ}-OD'\sin 35 ^{\circ}|

\Rightarrow |PQ|=|250\sin 20 ^{\circ}-230\sin 35 ^{\circ}|

\Rightarrow |PQ|=46.42 miles

Now, from equations (i) and (ii), we have

|DD'|=\sqrt{|45.52|^2+|46.42|^2}=65.01 miles, and

\tan \alpha=\frac{|46.42|}{|45.52|}

\alpha=\tan^{-1}\left(\frac{|46.42|}{|45.52|}\right)=45.56 ^{\circ}

Hence, the wind pushed the plane 65.01 miles in the direction of 45.56 ^{\circ} E astof North  with respect to the destination point.

5 0
3 years ago
A game room has a floor that is 100 feet by 30 feet. A scale drawing of the floor on grid paper uses a scale of 3 units:5 feet.
Ghella [55]
3 units/ 5 feet = 60 units/ 100 feet
3 units/ 5 feet = 18 units/ 30 feet

The dimensions of the scale drawing are 60 units by 18 units.

Hope this helps!
7 0
3 years ago
Need help with my Geometry, can someone help me with 4,5 and 10?
xz_007 [3.2K]
For questions 4 and 5, use laws of complementary and supplementary angles to find values of x. I'm not too sure about what question 10 is asking.

Hope I helped :)

6 0
3 years ago
Read 2 more answers
WHICH OF THE FOLLOWING COMPARISONS IS FALSE A. 4 LITERS < 1 GALLON B. 1 FOOT < 1 METER C. 25 GRAMS < 1 OUNCE D. 10 KILO
Kisachek [45]
Ummm search it up on google it should be on there
4 0
3 years ago
What is the area of the composite figure?
s344n2d4d5 [400]

Answer:

the answer is 96 squared feet

7 0
3 years ago
Read 2 more answers
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