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mixer [17]
2 years ago
12

The figure shows two triangles on the coordinate grid:

Mathematics
1 answer:
Masja [62]2 years ago
5 0

The correct statement is "A translation 5 units to the right, followed by a 180-degree counterclockwise rotation about the origin"

A=(-4,-1), B=(-3,-1), C=(-4,-4)

A'=(-1,1), B'=(-2,1), C'=(-1,1)

<u>Option A:</u>  

A=(-4,-1)

Translate 5 units up, we get (-4,-1+5)=(-4,4).

When rotating a point 270 degrees counterclockwise about the origin our point A(x,y) becomes A'(y,-x).

So, 270-degree counterclockwise rotation about the origin will give (4,4).

This is not equal to (-1,1).

So, this option is incorrect.

<u>Option B:</u>  

A=(-4,-1)

When rotating a point 270 degrees counterclockwise about the origin our point A(x,y) becomes A'(y,-x).

So, 270-degree counterclockwise rotation about the origin will give (-1,4).

Now, translating 5 units up, we get (-1,4+5)=(-1,9)

This is not equal to (-1,1).

So, this option is incorrect.

<u>Option C:  </u>

A=(-4,-1)

When rotating a point 180 degrees counterclockwise about the origin our point A(x,y) becomes A'(-x,-y).

So, 180-degree counterclockwise rotation about the origin will give (4,1).

Now, translating 5 units right, we get (4+5,1)=(9,1)

This is not equal to (-1,1).

So, this option is incorrect.

<u>Option D:  </u>

A=(-4,-1)

Translate 5 units right, we get (-4+5,-1)=(1,-1).

When rotating a point 180 degrees counterclockwise about the origin our point A(x,y) becomes A'(-x,-y).

So, 180-degree counterclockwise rotation about the origin will give (-1,1).

This is equal to (-1,1).

So, this option is correct.

Learn more about translation and rotation here:

brainly.com/question/15577335?referrer=searchResults

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CaHeK987 [17]

The equation of a sphere centered at (h, j, k) with radius r is

... (x -h)² +(y -j)² +(z -k)² = r²

Your sphere has center (-9, 4, 1) and radius 4, so its equation is

... (x +9)² +(y -4)² +(z -1)² = 16

This can be written in general form as

... x² + y² + z² +18x -8y -2z +82 = 0

5 0
3 years ago
What’s the correct answer for this ?
pickupchik [31]

Answer:

Blank 1) 150

Blank 2) (3)²

3) (4)²

4) (x+3)²

5) (y-3)²

6) (x+3)²+(y-3)² = 100

6 0
3 years ago
Could someone please help me:) I am stick and I am not sure what to do ​
Delicious77 [7]

Answer:

Part 5.1.1:

\displaystyle \cos 2A = \frac{7}{8}

Part 5.1.2:

\displaystyle \cos A = \frac{\sqrt{15}}{4}

Step-by-step explanation:

We are given that:

\displaystyle \sin 2A = \frac{\sqrt{15}}{8}

Part 5.1.1

Recall that:

\displaystyle \sin^2 \theta + \cos^2 \theta = 1

Let θ = 2<em>A</em>. Hence:

\displaystyle \sin ^2 2A + \cos ^2 2A = 1

Square the original equation:

\displaystyle \sin^2 2A = \frac{15}{64}

Hence:

\displaystyle \left(\frac{15}{64}\right) + \cos ^2 2A = 1

Subtract:

\displaystyle \cos ^2 2A = \frac{49}{64}

Take the square root of both sides:

\displaystyle \cos 2A = \pm\sqrt{\frac{49}{64}}

Since 0° ≤ 2<em>A</em> ≤ 90°, cos(2<em>A</em>) must be positive. Hence:

\displaystyle \cos 2A = \frac{7}{8}

Part 5.1.2

Recall that:

\displaystyle \begin{aligned}  \cos 2\theta &= \cos^2 \theta - \sin^2 \theta \\ &=   1- 2\sin^2\theta \\ &= 2\cos^2\theta - 1\end{aligned}

We can use the third form. Substitute:

\displaystyle \left(\frac{7}{8}\right) = 2\cos^2 A - 1

Solve for cosine:

\displaystyle \begin{aligned} \frac{15}{8} &= 2\cos^2 A\\ \\ \cos^2 A &= \frac{15}{16} \\ \\ \cos A& = \pm\sqrt{\frac{15}{16}} \\ \\ \Rightarrow \cos A &= \frac{\sqrt{15}}{4}\end{aligned}

In conclusion:

\displaystyle \cos A = \frac{\sqrt{15}}{4}

(Note that since 0° ≤ 2<em>A</em> ≤ 90°, 0° ≤ <em>A</em> ≤ 45°. Hence, cos(<em>A</em>) must be positive.)

4 0
3 years ago
Please Help!!!!
Dima020 [189]
Aight, I gotchu.
Combine like terms,
4p > - 11
p < -3
To get p by itself you must flip the symbol

6p < 36 
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To get p by itself you must flip the symbol
Answer is D
6 0
4 years ago
Read 2 more answers
Solve the nonlinear inequality. Express the solution using interval notation. -7&lt;3-2x&lt;-2
erastova [34]

Answer:

5/2<x<5

Step-by-step explanation:

-7<3-2x<-2

or -7-3<-2x<-2-3

or -10<-2x<-5

or -10/-2>x>-5/-2

or 5>x>5/2

or 5/2<x<5

Therefore, 5/2<x<5 is the solution.

7 0
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