I think you probably meant <span>(x+2)^2+4 because the equation you have provided is not written in proper formatting and would actually be a straight line. However, if you meant for that second 2 to be an exponent, you now have a quadratic equation which would graph as a parabola. Remember the basic formula is y=(x-h)^2 +k where (h,k) is your vertex. So you change the sign of the number in the parenthesis, but not the number outside the parenthesis when finding the vertex. If there is a negative number in front of your equation, then the parabola is flipped upside down so the vertex would be a maximum, but if it is positive, or has nothing in front of it, then the parabola sits up like a bowl so the vertex is a minimum.</span>
Answer:
X=9 Y= 3
Step-by-step explanation:
For a hyperbola

where

the directrix is the line

and the focus is at (0, c).
Here, we have c = 5, a² = 9, so b² = 5² - 9 = 16.
a = √9 = 3
b = √16 = 4
Your hyperbola's constants are ...
a = 3
b = 4
______
Please note that the equation of a hyperbola has a negative sign for one of the terms. The equation given in your problem statement is that of an ellipse.
Simply plug the number after the semi colon into each question's respective variable.
1. Is k=-1 a solution to this problem?
Is 9(-1)=10-(-1)?
we see that -9=10+1=11 which is not a true equality. since -9 is not 11 then "No" is the correct answer to number 1.
3.
3(-10)÷(-6)=5-(-10) ?
-30÷-6=5+10?
5=15?
No, not true, thus "No" is the correct answer.
5. 8-8=2(8)-16?
Is 0=16-16 ?
Yes!
7.
Is 2(7-2)-5(7)=5(2-7)?
2(5)-35=5(-5)?
10-35=-25
-25=-25
Bingo! Yes.