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Anestetic [448]
2 years ago
11

I need help on these 2 questions how did I get it wrong? and for question 3 I'm not supposed to have the = sign so what am I sup

posed to replace it with?​

Mathematics
2 answers:
dmitriy555 [2]2 years ago
5 0

Answer:

3.

m + 7 ≥ 20

Subtract 7 on both sides,

m ≥ 20 - 7

m ≥ 13

The answer is m ≥ 13.

( you need to include both > and =, that is ≥ )

4.

2.1x = 23.1

Divide 2.1 on both sides,

x = 23.1 / 2.1

x = 11

trasher [3.6K]2 years ago
5 0

Answer:

For problem #3, we are given m+7\geq 20 so we would just subtract 7 from both sides to get rid of the 7 on the left and that would end up subtracting 7 from 20 also leaving us with m\geq 13.

For problem #4, we are given 2.1x=23.1 so we would just divide both sides by 2.1 which would get rid of the 2.1 on the left and that would also make us divide 23.1 by 2.1 leaving us with x=11.

<u><em>Hope this helps!  Let me know if you have any questions</em></u>

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Answer:

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Step-by-step explanation:

(A)

For a left skewed distribution the Mean < Median < Mode.

For a right skewed distribution the Mean > Median > Mode.

For a symmetric distribution the Mean = Median = Mode.

Given: Mean = 78.2, Median = 67 and Mode = 67

In this case the mean of the data is more than the median and mode.

Mean = 78.2>Median = Mode = 67

Thus, the data set of the sample of students who has taken a calculus test is right skewed.

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Combined average (\mu_{c}) = 70

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Average of male students (\mu_{M}) = 73

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Average of female students = \mu_{F}

The formula to compute the combined average is:

\mu_{c}=\frac{n_{M}\mu_{M}+n_{F}\mu_{F}}{n_{M}+n_{F}}

Compute the value of \mu_{F} as follows:

\mu_{c}=\frac{n_{M}\mu_{M}+n_{F}\mu_{F}}{n_{M}+n_{F}}\\70=\frac{(20\times73)+(15\times\mu_{F})}{20+15}\\ 70\times35=1460+(15\times\mu_{F})\\\mu_{F}=\frac{2450-1460}{15} \\=66

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