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1 year ago

4. Find the area of the following composite figure.

Mathematics

2 answers:

inn [45]1 year ago

7 0

Answer:

The area is 136

Step-by-step explanation:

7 x 16 = 112

1/2 x 8 x 6 = 24

24 + 112 = 136

inna [77]1 year ago

6 0

Answer:

the area is 136cm²

Step-by-step explanation:

see the steps in the image

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What is (99/100)^101 times (100/99)^100?

sineoko [7]

Answer:

99/100

Step-by-step explanation:

First of all recall that

$a^n\cdot b^n =(ab)^n$

Now we we will try to apply that formula for $a=99/100$ and $b=100/99$ .

First rewrite $(99/100)^{101}=(99/100)\times (99/100)^{100}$

Now

$(99/100)\times (99/100)^{100}\times (100/99)^{100}\\=(99/100)\times ((99/100)\times (100/99))^{100}\\=(99/100)\times 1^{100}\\=(99/100)\times 1\\=99/100$

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3 years ago

9x^2-6x+8=0 what is the fifth step in solving this equation

Simora [160]

Answer:

write the equation as a binomial

Step-by-step explanation:

8 0

2 years ago

Thank you in advance for those who provided support to my question!

alekssr [168]

GCF of 10 and 12 is 2

LCM of 16 and 24 is 48

Added together is 50

5 0

3 years ago

Read 2 more answers

What is the predicted difference in sleep between individuals A and B, where individual A has 12 years of education and works 20

kari74 [83]

Answer: The predicted difference in sleep is 1251437 minutes.

Step-by-step explanation:

Since we have given that

Number of years of education = 12 years

Number of minutes a week = 2000

As we have

In case of individual A:

7 days = 2000 minutes

1 year = 365 days = $\dfrac{2000}{7}\times 365=104285$

12 years = $104285\times 12=1251420\ minutes$

In case of individual B:

7 days = 3000 minutes

1 year = 365 days = $\dfrac{3000}{7}\times 365=156428$

16 years = $156428\times 16=2502857$ minutes

So, the predicted difference in sleep between individuals A and B is given by

$2502857-1251420\\\\=1251437\ minutes$

Hence, the predicted difference in sleep is 1251437 minutes.

7 0

3 years ago

Breyers is a major producer of ice cream and would like to test if the average American consumes more than 17 ounces of ice crea

asambeis [7]

Answer:

The conclusion for this hypothesis test would be that the average American consumes less than or equal to 17 ounces of ice cream per month.

Step-by-step explanation:

We are given that Breyers is a major producer of ice cream and would like to test if the average American consumes more than 17 ounces of ice cream per month.

A random sample of 25 Americans was found to consume an average of 19 ounces of ice cream last month. The standard deviation for this sample was 5 ounces.

Let $\mu$ = average ounces of ice cream consumed by American per month

So, Null Hypothesis, $H_0$ : $\mu \leq$ 17 ounces {means that the average American consumes less than or equal to 17 ounces of ice cream per month}

Alternate Hypothesis, $H_A$ : $\mu$ > 17 ounces {means that the average American consumes more than 17 ounces of ice cream per month}

The test statistics that will be used here is One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average = 19 ounces

s = sample standard deviation = 5 ounces

n = sample of Americans = 25

So, test statistics = $\frac{19-17}{\frac{5}{\sqrt{25} } }$ ~ $t_2_4$

= 2

The value of the test statistics is 2.

Now at 0.025 significance level, the t table gives critical value of 2.06 at 24 degree of freedom for right-tailed test. Since our test statistics is less than the critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the the average American consumes less than or equal to 17 ounces of ice cream per month.

8 0

3 years ago