The option that describes the relationship between the two confidence intervals is; The width of I₈₁ will be¹/₉ the width of I₉
<h3>How to calculate width of the confidence interval with normal distribution?</h3>
The width of the confidence interval will be calculated from the formula;
W = 2Z(σ/√n)
where;
z is the z-score at given confidence level
σ is standard deviation
n is sample size
For first sample;
W_i9 = 2Z(σ/√9)
W_i9 = ²/₃Zσ
For second Sample;
W_i81 = 2Z(σ/√81)
W_i81 = ²/₉Zσ
Thus, we will have;
W_i9/W_i81 = (²/₃Zσ)/(²/₉Zσ)
W_i9/W_i81 = 9
W_i81 = ¹/₉W_i9
Read more about width of confidence interval at; brainly.com/question/15934877
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Answer: The radius are the same.
Explanation:
Any two circles with the same radius are congruent
line segments from the center point of a circle to each corner of the triangle are radius
if one circle is moved so that its centre coincides with the centre of the other circle, then it follows from the definition that the two circles will coincide.
