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a_sh-v [17]
2 years ago
15

Which of the following statements is true about the solution of the system

Mathematics
2 answers:
Zigmanuir [339]2 years ago
8 0
There are no solutions
Natali [406]2 years ago
6 0

Answer:

there are no solutions

Step-by-step explanation:

- 8x + 12y = 4 → (1)

2x - 3y = 3 → (2)

multiply (2) by 4

8x - 12y = 12 → (3)

add (1) and (3) term by term

0 + 0 = 16 , that is

0 = 16 ← not possible

this indicates the system has no solutions

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Step-by-step explanation:

Multiply each by 8 to continue the linear relationship.

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Cual número entero tiene 2×5 como factorizacion prima​
Sophie [7]

Answer:

10

Step-by-step explanation:

3 0
3 years ago
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You own Everything's Coming Up Roses flower shop. Your employee makes 4 deliveries per hour. The distance between the shop and t
qaws [65]
We have 4 deliveries ( 12 1/3 , 8 3/4, 17 2/8 and 23 2/3 miles ) and also the final delivery : 10 5/10 miles = 10 1/2 miles.
We have to add up all the deliveries and to divide the result by 5:
( 12 1/3 + 8 3/4 + 17 1/4 + 23 2/3 + 10 1/2 ) : 5 =
= 72 1/2 : 5 = 72.5 : 5 = 14.5 = 14 1/2
Answer: The average distance for all segments of this trip is 14 1/2 miles. 
4 0
3 years ago
Calculate pt3 such that a line from pt1 to pt3 is perpendicular to the line from pt1 to pt2, and the distance between pt1 and pt
Leni [432]
Let the point_1 = p₁ = (1,4)
and      point_2 = p₂ = (-2,1)
and      Point_3 = p₃ = (x,y)

The line from point_1 to point_2 is L₁ and has slope = m₁
The line from point_1 to point_3 is L₂ and has slope = m₂
m₁ = Δy/Δx = (1-4)/(-2-1) = 1
m₂ = Δy/Δx = (y-4)/(x-1)
L₁⊥L₂ ⇒⇒⇒⇒ m₁ * m₂ = -1
∴ (y-4)/(x-1) = -1 ⇒⇒⇒ (y-4)= -(x-1)
(y-4) = (1-x) ⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒ equation (1)

The distance from point_1 to point_2 is d₁
The distance from point_1 to point_3 is d₂
d = \sqrt{Δx^2+Δy^2}
d₁ = \sqrt{(-2-1)^2+(1-4)^2}
d₂ = \sqrt{(x-1)^2+(y-4)^2}
d₁ = d₂
∴ \sqrt{(-2-1)^2+(1-4)^2} = \sqrt{(x-1)^2+(y-4)^2} ⇒⇒ eliminating the root
∴(-2-1)²+(1-4)² = (x-1)²+(y-4)²
 (x-1)²+(y-4)² = 18
from equatoin (1)  y-4 = 1-x
∴(x-1)²+(1-x)² = 18            ⇒⇒⇒⇒⇒ note: (1-x)² = (x-1)²
2 (x-1)² = 18
(x-1)² = 9
x-1 = \pm \sqrt{9} = \pm 3
∴ x = 4 or x = -2
∴ y = 1 or y = 7

Point_3 = (4,1)  or  (-2,7)












8 0
3 years ago
What will the graph look like for a system of equations that has no solution?
lyudmila [28]

Answer:

D

Step-by-step explanation:

The solution to a systems of equations is the intersection point of the lines. If no solution is possible then their is no intersection point. The lines must be parallel.

8 0
2 years ago
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