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2 years ago

The coordinate plane shows the floor plan for a swimming pool. What is the area of the pool's border?

Mathematics

1 answer:

LekaFEV [45]2 years ago

7 0

Answer:

border area: 100 m²

Step-by-step explanation:

The area of the pool border will be the overall area of the pool and boder, less the area of the pool. The area of each rectangle is the product of its length and width. The length and width of each can be found using the Pythagorean theorem.

<h3>Pythagorean Triple</h3>

The triple (3, 4, 5) is called a Pythagorean triple, because ...

3² +4² = 5²

That is, a triangle with sides of lengths 3, 4, and 5 will be a right triangle with a hypotenuse of length 5.

<h3>Application to Pool/Border Dimensions</h3>

We notice that the sides of the rectangles in the figure have a rise/run of ±3/4 or ±4/3. In each case, the side of the rectangle is the hypotenuse of a triangle with dimensions a multiple of 3 or 4 meters. Hence the hypotenuse (rectangle side length) is the corresponding multiple of 5 meters. The attachment illustrates this point, showing a triangle with sides that are (6, 8, 10), 2 times the basic triple.

The pool is 5 m by 10 m, for an area of ...

A = LW = (10 m)(5 m) = 50 m²

The overall area is 10 m by 15 m, for an area of ...

A = (15 m)(10 m) = 150 m²

<h3>Border Area</h3>

The pool's border is the difference between the overall area and the pool area:

150 m² -50 m² = 100 m² . . . . area of pool's border

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What is the function g(x) created from f(x) = x^2 by moving the graph left 9 units, vertically stretching it by a factor of 4, a

MariettaO [177]

<u>Given</u>:

The parent function is $f(x)=x^2$

We need to determine the function g(x) created from the function f(x) by moving the graph left 9 units, vertically stretching it by a factor of 4, and shifting the graph up 5 units.

<u>Shift left 9 units:</u>

The rule to shift the graph c units to the left is given by

$y=f(x+c)$

where c is the positive real number.

Hence, to shift the graph 9 units to the left is given by

$f(x)=(x+9)^2$

<u>Vertical stretch by a factor of 4:</u>

The rule to stretch the graph vertically by a factor of c is given by

$y=cf(x)$

where $c>1$

Hence, to stretch the graph vertically by a factor of 4, we have;

$f(x)=4(x+9)^2$

<u>Shifting 5 units up:</u>

The rule to shift the graph c units upward is given by

$y=f(x)+c$

where c is the positive real number.

Hence, to shift the graph 5 units upward is given by

$f(x)=4(x+9)^2+5$

Therefore, the function $g(x)=4(x+9)^2+5$ is created from the graph $f(x)=x^2$ by moving the graph left 9 units, vertically stretching it by a factor of 4 and shifting up 5 units.