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Alinara [238K]
3 years ago
9

Choose the function whose graph is given by:

Mathematics
1 answer:
Murljashka [212]3 years ago
7 0

Answer:

The answer is D

Step-by-step explanation:

We should note that the function y = sin x = b/r has a maximum value of 1 at x = π/2, since at that point b is equal to r

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Find the exact value of sin2 theta given sin theta =5/13, 90°<theta <180°
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Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.

\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{13}}\impliedby \textit{now let's find the \underline{adjacent side}}&#10;\\\\\\&#10;\textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}

\bf \pm\sqrt{13^2-5^2}=a\implies \pm\sqrt{144}=a\implies \pm 12 =a \implies \stackrel{II~quadrant}{-12=a}&#10;\\\\\\&#10;therefore \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{-12}}{\stackrel{hypotenuse}{13}}&#10;\\\\&#10;-------------------------------\\\\&#10;sin(2\theta )\implies 2sin(\theta )cos(\theta )\implies 2\left(\frac{5}{13}  \right)\left( \frac{-12}{13} \right)\implies -\cfrac{120}{169}
3 0
4 years ago
Point Q' is the image of Q(-7, -6) under the translation (x, y) + (x + 12, y + 8).
Lina20 [59]

Answer:

The co-ordinates of Q' is (5,2).

Step-by-step explanation:

Given:

Pre-image point

Q(-7,-6)

To find Image point Q' after following translation.

(x,y)\rightarrow (x+12,y+8)

Solution:

Translation rules:

Horizontal shift:

(x,y)\rightarrow (x+k,y)

when K>0 the point is translated k units to the right.

when K the point is translated k units to the left.

Vertical shift:

(x,y)\rightarrow (x,y+k)

when K>0 the point is translated k units up.

when K the point is translated k units down.

Given translation (x,y)\rightarrow (x+12,y+8) shows the point is shifted 12 units to the right and 8 units up.

The point Q' can be given as:

Q'=(-7+12,-6+8)=(5,2)

So, the co-ordinates of Q' is (5,2). (Answer)

7 0
3 years ago
Explain why there can be no infinite geometric series with a first term of 12 and a sum of 5.
Iteru [2.4K]

Answer:

Step-by-step explanation:

When you find the sum of a number you are adding two or more numbers together. therefore the only answer that you could use to get a sum of 5 when your first term is 12 would be -7

3 0
3 years ago
An amoeba splits to form two amoebas after one hour. One hour later, each of the two amoebas split to form two more. Every hour,
andriy [413]

Answer:

Step-by-step explanation:

After 2 hour 4 amebe and after 6 hour 48 ambebe

2 ^2 =4 amebe

2^6 =48 amebe

8 0
3 years ago
find the coordinates of the points D ( 4, -4 ) and E ( 5, -5 ) after the transformation ( x; y ) ( x + 3, y -5
postnew [5]

Answer:

second option

Step-by-step explanation:

Given the rule

(x, y ) → (x + 3, y - 5)

This means add 3 to the original x- coordinate and subtract 5 from the original y- coordinate, that is

D(4, - 4 ) → D'(4 + 3, - 4 - 5 ) → D'(7, - 9 )

E(5, - 5 ) → E'(5 + 3, - 5 - 5 ) → E'(8, - 10 )

7 0
3 years ago
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