Question

1.

Answer 1

The solution to the given indices are 1/2^7, 11^4 and -1/64

Indices expression

Give the following indices expression

$\frac{(2^{-4})^2\times 2^{-5}}{2^{-6}}$

This can be further simplified according to the law of indices as:

$\frac{(2^{-4})^2\times 2^{-5}}{2^{-6}} =\frac{2^{-8-5}}{2^{-6}}$

Determine the result

$\frac{2^{-8-5}}{2^{-6}} = 2^{-7} = 1/2^7$

For the indices expression

$11^{-4}\times 11^{8} = 11^{-4+8}=11^4$

For the indices expression

$-4^4\times4^{-7}\\=-(4^{4-7})\\= -4^{-3}\\=-1/4^3\\=-1/64$

Hence the solution to the given indices are 1/2^7, 11^4 and -1/64

Learn more on indices here: brainly.com/question/170984

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