First, let's deal with the fraction in the denominator of the exponent. Multiply the top and bottom of the exponent by 6.
Now that the fraction in the denominator is taken care of, we can reduce the denominator.
. Some professors might accept this as simplest form, but others might ask you to get rid of the negative.
In place of t, or theta, I'm going to utilize x instead. So the equation is -3*cos(x) = 1. Get everything to one side and we have -3*cos(x)-1 = 0
Let f(x) = -3*cos(x)-1. The goal is to find the root of f(x) in the interval [0, 2pi]
I'm using the program GeoGebra to get the task done of finding the roots. In this case, there are 2 roots and they are marked by the points A and B in the attachment shown
A = (1.91, 0)
B = (4.37, 0)
So the two solutions for theta are
theta = 1.91 radians
theta = 4.37 radians
10 to the power of 3 would be 1000.
2 to the power of 3 would be 8.
1000 x 8 = 8000
I hope this helped you <3
Answer:
6x
Step-by-step explanation:
x²+9-__=(x-3)²
lets dissosiate this one (x-3)²
(x-3)²=(x-3)(x-3)
=x²-3x-3x+9
=x²-6x+9 so x²+9-6x
so the answer is 6x
C
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