Given: y = 2x^2 - 32x + 56
1) y = 2 [ x^2 - 16x] + 56
2) y = 2 [ (x - 8)^2 - 64 ] + 56
3) y = 2 (x - 8)^2 - 128 + 56
4) y = 2 (x - 8)^2 - 72 <----------- answer
Minimum = vertex = (h,k) = (8, - 72)
=> x-ccordinate of the minimum = 8 <-------- answer
The direction you are traveling to get back home is North
What do you mean put in standard form?
Begin by subtracting 2b from both sides. This will give us
-ax > -2b +8
Then we will divide by -a. This division by a negative number changes the direction of the inequality sign. When we divide by -a:
