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Vitek1552 [10]
2 years ago
8

Choosing from 5 flavors and 2 sizes of juice what are the outcomes?

Mathematics
2 answers:
Ratling [72]2 years ago
6 0
10 is the answer to your question
svetoff [14.1K]2 years ago
3 0

Answer:

10

Step-by-step explanation:

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Suppose you were adding 527+405. What would the tens problem be
nydimaria [60]

it would be 3 because when you add it, it gets to be 932 and the tens place is 3.


8 0
3 years ago
I am a product one of my factors is 9 the sum of my two factors is 13 what number am i
lesya692 [45]
If 1 of ur factors is 9...and the sum of ur factors is 13....then ur other factor is (13 - 9) = 4

so u have 2 factors, 9 and 4, and u r the product, then u r (9 * 4) = 36 <==
3 0
3 years ago
The plans for a shed call for a rectangular floor with a perimeter of 276 ft. the length is two times the width. find the length
hichkok12 [17]
2l+2w=276
l=2w

2(2w)+2w=276
6w=276
w=46
l=92
6 0
3 years ago
A bin contains 25 light bulbs, 5 of which are in good condition and will function for at least 30 days, 10 of which are partiall
Ira Lisetskai [31]

Answer:

The probability that it will still be working after one week is \frac{1}{5}

Step-by-step explanation:

Given :

Total number of bulbs = 25

Number of bulbs which are good condition and will function for at least 30 days = 5

Number of bulbs which are partially defective and will fail in their second day of use = 10

Number of bulbs which are totally defective and will not light up = 10

To find : What is the probability that it will still be working after one week?

Solution :

First condition is a randomly chosen bulb initially lights,

i.e. Either it is in good condition and partially defective.

Second condition is it will still be working after one week,

i.e. Bulbs which are good condition and will function for at least 30 days

So, favorable outcome is 5

The probability that it will still be working after one week is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

\text{Probability}=\frac{5}{25}

\text{Probability}=\frac{1}{5}

5 0
3 years ago
Which is the best estimate of the difference between
Romashka-Z-Leto [24]

Answer:

c. 5

Step-by-step explanation:

678 rounds to 700 and 218 rounds to 200. 700-200=500

7 0
3 years ago
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