The rise should be -3 and the run should be 2, the line should also pass through 7.
You haven't provided neither the diagram nor the options.
Therefore, I cannot provide an exact answer, however, I will try to help you with the concept.
<u>For a triangle, the measure of each angle is proportional to the length of its opposite side.</u>
<u>This means that:</u>
1- The largest angle is the angle opposite to the longest side
2- The smallest angle is the angle opposite to the shortest side
Since you are looking for the largest angle, pick the one facing the longest side
<u>Some tips and tricks:</u>
<u>1- In a right angle triangle</u>, we know that the hypotenuse is the longest side, therefore, the largest angle would be the right angle
<u>2- In an obtuse triangle</u>, the largest angle is simply the obtuse angle itself (the one whose measure is greater than 90)
<u>3- In equilateral triangle</u>, all three angles are equal
Hope this helps :)
I use a calculator and made sure it was in degrees
Answer:
Both angles have a measure of 134degrees, y = 27degrees.
Step-by-step explanation:
As per what is given in the problem:
There are 2 parallel lines, both are intersected by a transversal.
Remember the theorem, when two parallel lines are intersected by a transversal, then the alternate exterior angles are congruent.
The is meanse that:
3y + 53 = 7y - 55
Solve using inverse operations:
3y + 53 = 7y - 55
+55 +55
3y + 108 = 7y
-3y -3y
108 = 4y
/4 /4
27 = y
Now, substitute back in to find the value of the angle:
3y + 53
y = 27
3 ( 27 ) + 53
81 + 53
= 134
Since the angles are alternate exterior, they are congruent, hence both angles have a measure of 134degrees.
