2(5k+1)
2x5x2+1 =21
K=2 | 21
2x5x3+1 =31
K=3 | 31
Answer:
P(Z < 2.37) = 0.9911.
Step-by-step explanation:
We are given that Let z denote a random variable that has a standard normal distribution.
Let Z = a random variable
So, Z ~ Standard Normal(0, 1)
As we know that the standard normal distribution has a mean of 0 and variance equal to 1.
Z = ~ N(0,1)
where, = mean = 0
= standard deviation = 1
Now, the probability that z has a value less than 2.37 is given by = P(Z < 2.37)
P(Z < 2.37) = P(Z < ) = P(Z < 2.37) = 0.9911
The above probability is calculated by looking at the value of x = 2.37 in the z table which has an area of 0.9911.
The class width for this Frequency Distribution Table is 5.
<h3>What is the class width?</h3>
The class width is the difference between the upper boundary and the lower boundary of the class.
The class width = upper boundary - lower boundary
5 - 0 = 5
To learn more about Frequency tables, please check: brainly.com/question/27344444
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Answer:
A
Step-by-step explanation:
x + 4 = ± 2
x = -2
x = -6
There are 31+42+50+61=184 total females, and 50+61=111 females in grades 11 and 12, so the percentage is 111/184*100=60.33 percent, which can be rounded to 60%.