The cost of bench is 325.
Step-by-step explanation:
Given,
Combined cost of table and bench = 725
Let,
x be the cost of garden table
y be the cost of bench
According to given statement;
x+y=725 Eqn 1
x = y+75 Eqn 2
Putting value of x from Eqn 2 in Eqn 1
Dividing both sides by 2
The cost of bench is 325.
Keywords: linear equation, substitution method
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Answer:
77°
Step-by-step explanation:
From the question given above, the following data were obtained:
Cos α = 0.93
Sine θ = 0.26
Tan β = 0.84
α + β + θ =?
Next, we shall determine the value of α. This can be obtained as follow:
Cos α = 0.93
Take the inverse of Cos
α = Cos¯¹ 0.93
α = 22°
Next, we shall determine the value of θ. This can be obtained as follow:
Sine θ = 0.26
Take the inverse of Sine
θ = Sine¯¹ 0.26
θ = 15°
Next, we shall determine the value of β. This can be obtained as follow:
Tan β = 0.84
Take the inverse of Tan.
β = Tan¯¹ 0.84
β = 40°
Finally, we shall determine the value of α + β + θ . This can be obtained as follow:
α = 22°
θ = 15°
β = 40°
α + β + θ = 22 + 40 + 15
α + β + θ = 77°
15*4= 60 (60 students in total)
180/60= 3 (180 book covers divided among 60 students)
Each student gets 3 covers.<span />
SV middle line of trapezoid, so
Answer: QR=18
Answer: 8π square meters
Explanation:
First, we convert the angle of the sector to radians, which is 30 degrees.
Note that 180 degrees is equal to π radians. Since 30 degrees is equal to 180 degrees divided by 6,
30 degrees = π/6 radians
Thus, the angle of the sector in radians is π/6.
So, the area of the sector is given by
(Area of sector) = (1/2)(radius)²(angle of the sector in radians)
= (1/2)(radius)²(π/6)
= (π/12)(radius)²
= (1/12)(π)(radius)²
Note that
(Area of the circle) = (π)(radius)² = 96π
Therefore, the area of the 30-degree sector is given by
(Area of the sector) = (1/12)(π)(radius)²
= (1/12)(Area of the circle)
= (1/12)(96π)
(Area of the sector) = 8π square meters