If I did this correctly, the answer should be 2.72. Monday's stock price is given to you already, 30.80. To find Tuesday's, you'd add 1.20 to the already existing 30.80, that totals to 32. To find the number for Wednesday you would have to get the percentage and move the decimal so you can multiply it, it should end at .0625. You then get that number and multiply it by 32 because it was Tuesday's amount. From that you should get 2. You then subtract the 2 and the total for Wednesday is 30. You do the same for Thursday, you get the already existing number, 30, and multiply it by .04. That should end in 1.2. You then subtract that 1.2 and you should get 28.8 as your answer for Thursday. For Friday, the steps repeat. You take the 28.8 and multiply it by .025. That should equal to .72. You now subtract that .72 from Thursday's amount and should be left with 28.08 for Friday. Now that all the numbers are known, take the numbers for Monday and for Friday and then subtract them. (30.80-28.08) It should equal to 2.72.
Answer: choice B
Angle A = 63 degrees
side a = 13.4
side b = 6.8
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Given Info:
Angle C = 90 degrees
Angle B = 27 degrees
side c = 15
What is needed to be found:
Angle A, side a, side b
Finding side a
cos(angle) = adjacent/hypotenuse
cos(B) = BC/AB
cos(B) = a/15
cos(27) = a/15
15*cos(27) = a
13.3650978628256 = a
a = 13.3650978628256
a = 13.4
Finding side b
Using the pythagorean theorem
a^2 + b^2 = c^2
(13.3650978628256)^2 + b^2 = 15^2
178.625840882906 + b^2 = 225
178.625840882906 + b^2 - 178.625840882906 = 225 - 178.625840882906
b^2 = 46.374159117094
sqrt(b^2) = sqrt(46.374159117094)
b = 6.809857496093
b = 6.8
Finding angle A
sin(angle) = opposite/hypotenuse
sin(A) = BC/AB
sin(A) = a/c
sin(A) = 13.3650978628256/15
sin(A) = 0.89100652418838
arcsin(sin(A)) = arcsin(0.89100652418838)
A = 63.0000000000016
A = 63
Answer:
we are given
part-A:
Since, x is number of tablets
C(x) is cost of producing x tablets
so, vertical box is C(x)
so, we write in vertical box is "cost of producing x tablets"
Horizontal box is x
so, we write in horizontal box is "number of tablets"
part-B:
we have to find average on [a,b]
we can use formula
we are given point as
a: (15 , 395)
a=15 and C(15)=395
b: (20, 480)
b=20 , C(20)=480
now, we can plug values
...........Answer
part-c:
we have to find average on [b,c]
we can use formula
we are given point as
b: (20, 480)
b=20 , C(20)=480
c:(25,575)
c=25 , C(c)=575
now, we can plug values
Answer:
It would really depend on what the choices were.
Step-by-step explanation:
