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saul85 [17]
2 years ago
6

Noah and Gabriel are in the same English class. They have taken 6 quizzes so far. Find the measures of center for each of the st

udents.
Noah’s scores: 84, 85, 85, 86, 90, 92


Total of 522


Gabriel’s scores: 82, 85, 86, 86, 90, 94


Total of 523


What are Noah’s mean, median, and mode?





What are Gabriel’s mean, median, and mode?
Mathematics
1 answer:
kow [346]2 years ago
6 0

Answer:

Not sure if you still want the answers but here you go

Step-by-step explanation:

Noah's mean: 87

Noah's median: 85.5

Noah's mode: 85

Gabriel's mean: 87.17

Gabriel's median: 86

Gabriel's mode: 86

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Amanda's parents had a birthday dinner for her at Sushi Yama restaurant. The bill came to $74 before the tip. They left an 18% t
Vika [28.1K]

Answer:

<h2>$87.32</h2>

Step-by-step explanation:

Step one:

given data

we are told that the initial bill is $74

thereafter they gave a tip worth 18% of the bill

let us compute what 18% of $74 will amount to

Step two:

=18/100*74

=0.18*74

=$13.32

The added expenses is $13.32

Hence the total cost is

the initial bill plus the tip

=74+13.32

=$87.32

3 0
3 years ago
Need help with this question!
rosijanka [135]
Not sure:((((((( sorrryyyy
3 0
3 years ago
Read 2 more answers
A study found that a 95% confidence interval for the mean μ of a particular population was computed from a random sample of 1200
kotykmax [81]

Answer:

95% confidence interval for the mean μ is (6,14)

The Population mean μ lies between ( 6, 14 )

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given random sample 'n' = 1200

95% confidence interval for the mean μ is determined by

        (x^{-} -Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} +Z_{\alpha } \frac{S.D}{\sqrt{n} } )

Level of significance = 95% 0r 0.05

Z₀.₀₅ = 1.96

   (x^{-} -Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} +Z_{\alpha } \frac{S.D}{\sqrt{n} } ) = 10 ± 4

Mean of the small sample = 10

95% of confidence intervals are

                         ( 10 ±4 )

                  ( 10 -4 , 10+4)

                  ( 6 , 14 )

95% confidence interval for the mean μ lies between ( 6, 14 )

8 0
3 years ago
The probability that a certain hockey team will win any given game is 0.3723 based on their 13 year win history of 385 wins out
Whitepunk [10]

Answer:

0.1505 = 15.05% probability that the hockey team wins 6 games in November

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So p = 0.3723

12 games in November

So n = 12

What is the probability that the hockey team wins 6 games in November?

This is P(X = 6)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{12,6}.(0.3723)^{6}.(1-0.3723)^{6} = 0.1505

0.1505 = 15.05% probability that the hockey team wins 6 games in November

4 0
3 years ago
The office and the living room in a tiny house share a wall. The area of the office is 28 square feet. The area of the living ro
Mandarinka [93]

Answer: The 2 answers are

7・4 + 7・9

and

7(4+9)

Hope this helps!✦

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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