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gregori [183]
3 years ago
12

The solution to 3x2 – 12x 24 = 0 is .

SAT
1 answer:
kupik [55]3 years ago
4 0

Answer:

-9x28=0

Explanation:

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Find the units' digit in the product:
Otrada [13]
6, because it only depends on the last digits, 8*2 = 16, so 6! :)
3 0
3 years ago
All the actresses brought (her, their) scripts
Vikentia [17]

Answer:

their

Explanation:

Lets highlight the keywords in this sentence.

All the actresses brought (her, their) scripts.

The words all and actresses are telling you that there are more than 1 actress, so we will refer to them as 'their'.

4 0
2 years ago
Read 2 more answers
the height of a bottle rocket, in meters, is given by the function s(t)=−9t2+103t+403. find the average velocity of the bottle r
zaharov [31]

The average velocity of the bottle rocket are two given time intervals is 30 m/s and 20 m/s respectively, while the instantaneous velocity at 4.5 seconds is 22 m/s.

The given parameters;

  • s(t) = -9t² + 103t + 403
  • time interval (4.499, 4.5), and (4.5, 4.501)

The average velocity of the bottle rocket over the intervals is calculated as follows;

when the interval = [<em>4.499, 4.5</em>]

s(4.499)= -9(4.499)^2  + 103(4.499) + 403 = 684.22 \ m\\\\s(4.5) =  -9(4.5)^2  + 103(4.5) + 403 = 684.25 \ m

v = \frac{\Delta \ s}{\Delta \ t} = \frac{684.25 - 684.22}{4.5 - 4.499} = 30 \ m/s

when the interval = [<em>4.5, 4.501</em>]

s(4.5) = -9(4.5)^2 + 103(4.5) + 403 = 684.25 \ m\\\\s(4.501) = -9(4.501)^2 + 103(4.501) + 403 =684.27 \ m\\\\v= \frac{684.27 - 684.25}{4.501-4.5} \\\\v = 20 \ m/s

The instantaneous velocity of the bottle rocket at time t=4.5;

v = \frac{d \ s(t)}{dt} = -18t + 103\\\\v(4.5) = -18(4.5) + 103\\\\v(4.5) = 22 \ m/s

Thus, the average velocity of the bottle rocket are two given time intervals is 30 m/s and 20 m/s respectively, while the instantaneous velocity at 4.5 seconds is 22 m/s.

Learn more here: brainly.com/question/25009886

7 0
2 years ago
An event with a probability of 0 is an event with a probability of 1 is.
vichka [17]

Answer:

An event with a probability of 0 is Impossible. ✔

An event with a probability of 1 is Certain. ✔

Hope I have  Helped ❤

3 0
3 years ago
What is the excess reactant in the combustion of 211 g of methane in an open atmosphere?.
MAXImum [283]

The excess reactant in the combustion of 211 g of methane in an open atmosphere is oxygen, O₂

<h3>What is a combustion reaction? </h3>

A combustion reaction is a reaction in which a substance burns in air (oxygen) to produce carbon dioxide and water.

<h3>Combustion of methane </h3>

Methane combust in air (oxygen) to produce carbon dioxide and water according to the following equation:

CH₄ + 2O₂ —> CO₂ + 2H₂O

From the question given above, we were told that 211 g of methane combust in an open atmosphere. This simply means that the amount of oxygen will be very high.

Therefore, we can conclude that oxygen will be the excess reactant since the reaction is carried out in an open atmosphere.

Learn more about stoichiometry:

brainly.com/question/14735801

6 0
3 years ago
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