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kap26 [50]
2 years ago
7

What are two ways you can find an equivalent ratio for 12/16

SAT
1 answer:
Y_Kistochka [10]2 years ago
3 0

Answer:

1. Simplify the fraction

2. Muliply the fraction by a common multiple of the numerator and denominator

Explanation:

This fraction/ratio isn't in simplist form. We can simplify it to find an equivalent ratio.

\frac{12/2}{6/2} =\frac{6}{3}

We can keep simplifying to find more equivalent ratios.

\frac{6}{3} =\frac{2}{1} =2

---------------------------

As for multiplying, two ratios are equivalent to each other if one of them can be expressed as the multiple of the other. We can multiply both 12 and 16 by 2 to find an equivalent ratio.

\frac{12(2)}{16(2)} =\frac{24}{32}

You can keep multiplying by common multiples to find more equivalent ratios.

Thus, you can either simplify or multiply to find equivalent ratios.

hope this helps!

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Of the $10$ kids in a chess club, $5$ are left-handed and $5$ are right-handed. the club holds a round-robin tournament in which
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The total number of games a girl play against a boy is 25, the number of games a girl plays against a boy is 10, the fraction of the games are boy-versus-boy is 2/9, and 1/5 is the fraction of all games at the tournament Anita plays.

<h3>How to carry out Permutation and Combination?</h3>

We are given that there are 5 girls and 5 boys in a chess club.

Thus, total games that girls play against a boy = 5×5 = 25

The number of games a girl play against another is the total number of games = 10

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If Anita is one of the club members, then Anita will have to play against 9 people at the tournament.

Total number of games = 45

Then the fraction of all games at the tournament Anita play the game.= 9/45 ⇒ 1/5

Thus, the total number of games a girl play against a boy is 25, the number of games a girl plays against a boy is 10, the fraction of the games are boy-versus-boy is 2/9, and 1/5 fraction of all games at the tournament Anita plays.

Read more about Permutation and Combination at; brainly.com/question/4658834

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