Pls help i need this asap

Mathematics

1 answer:

Zielflug [23.3K]1 year ago

8 0

Answer:

Let x = # of commercials

y = # of movies

System of Equations:

x + y = 90

40x + 110y = 500

Step-by-step explanation:

We have to set our variables before we start solving. After setting the variables, we can set up the equations. If x = # of commercials and y = # of movies, then we can assume x + y = 90, as there have been a total of 90 commercials and movies played altogether. Then, we know that their worth is $500, so the price of all the commercials played and the price of all the movies played (which is 40x + 110y) sum to $500.

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At a fundraiser, students sold chocolate bars with almonds and chocolate bars with walnuts. The number of chocolate bars with al

BabaBlast [244]

Answer:

Total number chocolate bars with almonds sold were approximately 66.34 and total number chocolate bars with walnuts sold were approximately 34.67.

Step-by-step explanation:

Let number chocolate bars with almonds be x

Also let number chocolate bars with walnuts be y

Given:

Number of chocolate bars with almonds that were sold one weekend was 3 less than 2 times the number of chocolate bars with walnuts.

Framing the above sentence in equation form we get;

$x=2y -3$

Also given:

The number of chocolate bars with walnuts plus 4 times the number of chocolate bars with almonds was 300.

Framing the above sentence in equation form we get;

$4x+y=300$

Now Substituting the value of x in above equation we get;

$4x+y=300\\4(2y-3)+y=300\\8y-12+y=300\\9y=300+12\\9y=312\\\\y=\frac{312}{9} \approx 34.67$

Now we will substitute the value of y in equation $x=2y -3$ we get;

$x=2y-3 = 2\times34.67 -3 = 69.34-3\approx66.34$

Hence, Total number chocolate bars with almonds sold were approximately 66.34 and total number chocolate bars with walnuts sold were approximately 34.67.

6 0

3 years ago

For the functions f(x) = 6x – 1 and g(x) = 4x2 + x, find (gºf)(x). Provide your answer bolow

emmainna [20.7K]

For this case we have the following functions:

$f (x) = 6x-1\\g (x) = 4x ^ 2 + x$

We must find $(g_ {o} f) (x):$

By definition of composition of functions we have to:

$(g_ {o} f) (x) = g (f (x))$

So:

$(g_ {o} f) (x) = 4 (6x-1) ^ 2 + (6x-1) = 4 ((6x) ^ 2-2 (6x) (1) + (1) ^ 2) + 6x -1 = 4 (36x ^ 2-12x + 1) + 6x-1 = 144x ^ 2-48x + 4 + 6x-1 = 144x ^ 2-42x + 3$