I need help on this question plz

If the average of the numbers 3, 4, x, y, and 2 is 4, what is the value of x+y?

Amiraneli [1.4K]

Answer:

Step-by-step explanation:

(3+4+x+y+2)/5=4

9+x+y=20

x+y=20-9

x+y=11

6 0

3 years ago

What is the distance between home plate and second base

Ipatiy [6.2K]

Answer: idk you can figure it out urself

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Given the diagram below, if the area of the shaded region is 103 ft2, what are the dimensions of the inside triangle?

Yakvenalex [24]

Bigger rectangle:

we can see that

length is 3x-2

so, $L=3x-2$

width is x+6

so, $W=x+6$

now, we can find area

$A_b=L\times W$

$A_b=(3x-2)\times (x+6)$

Smaller rectangle:

we can see that

length is 2x

so, $L=2x$

width is x-1

so, $W=x-1$

now, we can find area

$A_s=L\times W$

$A_s=(2x)\times (x-1)$

Area of shaded region:

Area of shaded region = area of bigger rectangle - area of smaller rectangle

$A=A_b-A_s$

we can plug values

$A=((3x-2)\times (x+6))-((2x)\times (x-1))$

we are given that area as 103 ft^2

so, we can set it equal

$103=((3x-2)\times (x+6))-((2x)\times (x-1))$

now, we can solve for x

$103=x^2+18x-12$

$x^2+18x-12-103=103-103$

$x^2+18x-115=0$

now, we can factor it

$(x-5)(x+23)=0$

$x=5,x=-23$

Since, length can never be negative

so,

$x=5$

now, we can find dimensions of inner rectangle

Length is

$L=2\times 5$

$L=10ft$

width is

$W=5-1$

$W=4ft$

so, dimensions are

$L=10ft$

$W=4ft$ ..............Answer

5 0

4 years ago

Two bottles and their labels are mathematically similar.

Trava [24]

Answer:

The area of the larger label is 187.5 square centimeters.

Step-by-step explanation:

If the two bottles are mathematically similar, then the label area is directly proportional to the capacity of the bottle. If we know that a 0.512 L-bottle has a label area of 96 square centimeters, then the label area of a 1-L bottle is determined by this simple rule of three:

$x = 96\,cm^{2}\times \frac{1\,L}{0.512\,L}$

$x = 187.5\,cm^{2}$

The area of the larger label is 187.5 square centimeters.

3 0

3 years ago

At a certain gas station, 40% of the customers use regular gas (A1), 35% use plus gas (A2), and 25% use premium (A3). Of those c

grandymaker [24]

Answer:

a.)

P( A₂ ∩ B ) = P(B | A₂) × P(A₂)

P( A₂ ∩ B ) = 0.40 × 0.35

P( A₂ ∩ B ) = 0.14

b.)

P(B) = P( A₁ ∩ B ) + P( A₂ ∩ B ) + P( A₃ ∩ B )

P(B) = 0.08 + 0.14 + 0.125

P(B) = 0.345

c.)

For regular gas:

P(A₁ | B) = P( A₁ ∩ B ) / P(B)

P(A₁ | B) = 0.08 / 0.345

P(A₁ | B) = 0.232

For plus gas:

P(A₂ | B) = P( A₂ ∩ B ) / P(B)

P(A₂ | B) = 0.14 / 0.345

P(A₂ | B) = 0.406

For premium gas:

P(A₃ | B) = P( A₃ ∩ B ) / P(B)

P(A₃ | B) = 0.125 / 0.345

P(A₃ | B) = 0.362

Step-by-step explanation:

We are given the following information

40% of the customers use regular gas (A2)

P(A₁) = 0.40

35% use plus gas (A2)

P(A₂) = 0.35

25% use premium (A3)

P(A₃) = 0.25

Of those customers using regular gas, only 20% fill their tanks (event B).

P(B | A₁) = 0.20

Of those customers using plus, 40% fill their tanks

P(B | A₂) = 0.40

Whereas of those using premium, 50% fill their tanks.

P(B | A₃) = 0.5

a) What is the probability that the next customer will request plus gas and fill their tank?

We are asked to find P(A₂ ∩ B) = ?

Recall that Multiplicative law of probability is given by

P( A₂ ∩ B ) = P(B | A₂) × P(A₂)

P( A₂ ∩ B ) = 0.40 × 0.35

P( A₂ ∩ B ) = 0.14

b) What is the probability that the next customer fills the tank?

We are asked to find P(B) = ?

P(B) = P( A₁ ∩ B ) + P( A₂ ∩ B ) + P( A₃ ∩ B )

P( A₂ ∩ B ) is already calculated, we need to calculate

P( A₁ ∩ B ) and P( A₃ ∩ B )

So,

P( A₁ ∩ B ) = P(B | A₁) × P(A₁)

P( A₁ ∩ B ) = 0.20 × 0.40

P( A₁ ∩ B ) = 0.08

P( A₃ ∩ B ) = P(B | A₃) × P(A₃)

P( A₃ ∩ B ) = 0.50 × 0.25

P( A₃ ∩ B ) = 0.125

Finally,

P(B) = P( A₁ ∩ B ) + P( A₂ ∩ B ) + P( A₃ ∩ B )

P(B) = 0.08 + 0.14 + 0.125

P(B) = 0.345

c) If the next customer fills the tank, what is the probability that the regular gas is requested? Plus? Premium

For regular gas:

P(A₁ | B) = P( A₁ ∩ B ) / P(B)

P(A₁ | B) = 0.08 / 0.345

P(A₁ | B) = 0.232

For plus gas:

P(A₂ | B) = P( A₂ ∩ B ) / P(B)

P(A₂ | B) = 0.14 / 0.345

P(A₂ | B) = 0.406

For premium gas:

P(A₃ | B) = P( A₃ ∩ B ) / P(B)

P(A₃ | B) = 0.125 / 0.345

P(A₃ | B) = 0.362

5 0

4 years ago