Answer:
Step-by-step explanation:
each zero of the function will have a factor of (x - x₀)
h(x) = a(x + 3)(x + 2)(x - 1)
h(x) = a(x + 3)(x² + x - 2)
h(x) = a(x³ + 4x² + x - 6)
or the third option works if a = 1
however this equation gives us the points (0, -6) and (-1. -4), so "a" must be -2
h(x) = -2x³ - 8x² - 2x + 12
to fit ALL of the given points as it fits the three zeros and also h(0) and h(-1) so I guess that is why the given group is a <u><em>partial</em></u> set of solution sets
Answer:
Step-by-step explanation:
You have the following quadratic equation given in the problem:
You must make the equation equal to zero, as following:
Add like terms:
Now, to factor the equation, you must find two numbers whose sum is -2 and whose product is -15. Therefore, you have:
Answer:
2
Step-by-step explanation:
Answer:
y = (x - 3)² + 6
Step-by-step explanation:
the equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k ) are the coordinates of the vertex and a is a multiplier
Using the method of completing the square
y = x² - 6x + 15
add/subtract ( half the coefficient of the x- term )² to x² - 6x
y = x² + 2(- 3)x + 9 - 9 + 15
y = (x - 3)² - 9 + 15
y = (x - 3)² + 6 ← in vertex form
Tuesday at 2pm because 2 goes in 24 evenly. so whenever the 24 hours is up, she'll check it.
