I took the liberty of finding for the complete question.
And here I believe that the problem asks for the half life of Curium. Assuming
that the radioactive decay of Curium is of 1st order, therefore the
rate equation is in the form of:
A = Ao e^(-kt)
where,
A = amount after t years = 2755
Ao = initial amount = 3312
k = rate constant
t = number of years passed = 6
Therefore the rate constant is:
2755/3312 = e^(-6k)
-6k = ln (2755/3312)
k = 0.0307/yr
The half life, t’, can be calculated using the formula:
t’ = ln 2 / k
Substituting the value of k:
t’ = ln 2 / 0.0307
t’ = 22.586 years
or
t’ = 22.6 years
Answer:
The required inequality is: 
The graph is shown in figure.
Step-by-step explanation:
Consider the provided information.
Chad will need at least 24 minutes to complete the 5K race. However, he wants to finish in under 30 minutes.
Let the time taken to finish the race is represented by x.
Chad need at least 24 minutes and he wants to finish in under 30 minutes.
Thus, the required inequality is:

Now draw the graph of the inequality.
Use a dot or close circle to represents ≤ and use an open circle to represent <.
The value of x is greater than or equal to 24 but less than 30, Thus the required graph is shown in figure.
the answer i will give you is 72
25-3.5(3 1/2)=21.5. 21.5 pounds of roasted almonds were sold