find three numbers whos sum is 86, if the first number is three times the difference between the second and the third, and the s
1 answer:
Answer: 45,28,13
Step-by-step explanation:
Firstly let’s call integer 3
‘x’
Following the information given the following equations can be constructed:
integer 3 = x
integer 2 = 2+2x because 2x represents 2 times integer 3 (which is x) and plus two
integer 1 =3((2x+2)-x) what we have written is the difference between integer 2 (which was (2x+2)) and integer 3 which was x and simply multiply the result of that subtraction by 3
next we can treat them like their own variables almost.
integer 1 + integer 2 + integer 3 =86
so now plug in the equations we have constructed for each integer:
(3((2x+2)-x)) + (2x+2) + x = 86
to make it easier to read please see the image attached below to solve for x
After you have gone through the image I have included you should notice x= 13 great we got one integer! (Integer 3)
now plug in 13 into our integer equations :
integer 2: 2(13)+2= 28
Therefore integer 2 is 28
integer 1: 3((2(13)+2)-(13))=
3((28-13)
3(15)
45
Therefore integer 1 is 45.
and integer 3 is x which as we now know is equal to 13
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