Is the answer b?????
1 answer:
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Answer:
The discontinuity is x = 4
There no holes
The equation of the vertical asymptote is x = 4
The x intercept is 2
The equation of the horizontal asymptote is y = 1
Step-by-step explanation:
* Lets explain the problem
∵
- To find the point of discontinuity put the denominator = 0 and find
the value of x
∵ The denominator is x - 4
∵ x - 4 = 0 ⇒ add 4 to both sides
∴ x = 4
* The discontinuity is x = 4
- A hole occurs when a number is both a zero of the numerator
and denominator
∵ The numerator is x - 2
∵ x - 2 = 0 ⇒ add 2 to both sides
∴ x = 2
∵ The denominator is x - 4
∵ x - 4 = 0 ⇒ add 4 to both sides
∴ x = 4
∵ There is no common number makes the numerator and denominator
equal to 0
∴ There no holes
- Vertical asymptotes are vertical lines which correspond to the zeroes
of the denominator of the function
∵ The zero of the denominator is x = 4
∴ The equation of the vertical asymptote is x = 4
- x- intercept is the values of x which make f(x) = 0, means the
intersection points between the graph and the x-axis
∵ f(x) = 0
∴ ⇒ by using cross multiplication
∴ x - 2 = 0 ⇒ add 2 to both sides
∴ x = 2
* The x intercept is 2
- If the highest power of the numerator = the highest power of the
denominator, then the equation of the horizontal asymptote is
y = The leading coeff. of numerator/leading coeff. of denominator
∵ The numerator is x - 2
∵ The denominator is x - 4
∵ The leading coefficient of the numerator is 1
∵ The leading coefficient of the denominator is 1
∴ y = 1/1 = 1
* The equation of the horizontal asymptote is y = 1
Answer:
Option B is the correct choice.
Step-by-step explanation:
The graph is attached below.
We have to find the intercept meaning the value of the point on
when
So we will put the value of zero instead of
in our given equation.
So here we have solved it algebraically.
Putting
Multiplying both sides.
Adding both sides.
Dividing with both sides.
So the x-intercept of the given equation is which can be written as
in terms of coordinates.
Option B is the correct choice.
