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Harrizon [31]
2 years ago
5

Is the answer b?????

Mathematics
1 answer:
Lostsunrise [7]2 years ago
8 0

Answer:

it should be A if not im sorry

Step-by-step explanation:

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Plzzzzzzz help this is due soon and I have no clue what I'm doing lol. ​
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Answer:

1) x - 4 is greater than or equal to 18

x is greater than or equal to 22

2) 12 + x is less then or equal to 17

x is less the or equal to 5

3) 23 is less than x + 16

7 is less than x

4) -6 + x is greater than or equal to -7

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3 years ago
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A farmer is building a fence to enclose a rectangular area against an existing wall, shown in the figure below.
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3 years ago
How do I do 8b(ii) ? Please help me thank you!
Mila [183]
Step One
======
Find the length of FO (see below)

All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)

Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ

Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.

FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)]                                           \
OJ = ??

[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2      Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2    Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2   Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )

Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.


7 0
3 years ago
Solve t-v/r=k, for v
Arisa [49]

Answer:

t-v/r = k

t-k = v/r

v = r(t-k)

Hope this helps!

6 0
3 years ago
Which ordered pair gives the coordinates of the image of R(-a, b) if R is rotated clockwise 180°?
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Rotated 180° is(-b, a)
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3 years ago
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