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erma4kov [3.2K]
3 years ago
11

Please help anyone who great in math

Mathematics
1 answer:
max2010maxim [7]3 years ago
6 0

\huge\underline\mathcal{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>a </u><u>circle </u><u>along </u><u>with </u><u>the </u><u>measure </u><u>of </u><u>two </u><u>angles </u><u>at </u><u>the </u><u>centre</u>

  • To calculate - <u>measure </u><u>of </u><u>angle </u><u>JGH</u>

We know that ,

<u>the </u><u>sum </u><u>of </u><u>all </u><u>the </u><u>angles </u><u>at </u><u>the </u><u>centre </u><u>or </u><u>the </u><u>sum </u><u>of </u><u>all </u><u>the </u><u>central </u><u>angles </u><u>of </u><u>a </u><u>circle </u><u>equals </u><u>3</u><u>6</u><u>0</u><u>°</u>

\therefore \: \angle \: IGJ \:  +  \: \angle \: IGH \:  +  \: \angle \: JGH = 360\degree \:  \\  \\ \implies \: 125\degree + 149\degree + \angle \: JGH = 360\degree \\  \\ \implies \: 274\degree + \angle \: JGH = 360\degree \\  \\ \implies \: \angle \: JGH = 360\degree - 274\degree \\  \\ \implies \: \angle \: JGH = 86\degree

therefore , <u>option </u><u>(</u><u> </u><u>c </u><u>)</u><u> </u><u>8</u><u>6</u><u>°</u> is correct

hope helpful ~

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insens350 [35]

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bonufazy [111]

Answer: ABCD is a parallelogram.

Step-by-step explanation:

First we plot these point on a graph as given in attachment.

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also, AB ||CD, that will make ABCD a parallelogram ,  but to confirm we check the property of parallelogram "diagonals bisect each other" , i.e . "Mid point of both diagonals are equal".

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vladimir2022 [97]

Answer:

Step by Step Solution

More Icon

STEP

1

:

3

Simplify ——

x2

Equation at the end of step

1

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3

((((2•(x2))-5x)-——)+2x)-3

x2

STEP

2

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Equation at the end of step

2

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3

(((2x2 - 5x) - ——) + 2x) - 3

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STEP

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Rewriting the whole as an Equivalent Fraction

3.1 Subtracting a fraction from a whole

Rewrite the whole as a fraction using x2 as the denominator :

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STEP

4

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Pulling out like terms

4.1 Pull out like factors :

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Add the two equivalent fractions which now have a common denominator

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Equation at the end of step

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(2x4 - 5x3 - 3)

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Lelechka [254]
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