Please help anyone who great in math
1 answer:

- Given - <u>a </u><u>circle </u><u>along </u><u>with </u><u>the </u><u>measure </u><u>of </u><u>two </u><u>angles </u><u>at </u><u>the </u><u>centre</u>
- To calculate - <u>measure </u><u>of </u><u>angle </u><u>JGH</u>
We know that ,
<u>the </u><u>sum </u><u>of </u><u>all </u><u>the </u><u>angles </u><u>at </u><u>the </u><u>centre </u><u>or </u><u>the </u><u>sum </u><u>of </u><u>all </u><u>the </u><u>central </u><u>angles </u><u>of </u><u>a </u><u>circle </u><u>equals </u><u>3</u><u>6</u><u>0</u><u>°</u>

therefore , <u>option </u><u>(</u><u> </u><u>c </u><u>)</u><u> </u><u>8</u><u>6</u><u>°</u> is correct
hope helpful ~
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I believe it’s y=3x+8 I hope this helps :)
(2,5)
You just reverse it. Imagine folding the graph in half along the line. :)
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X=-2
Step-by-step explanation:
Let no =X
So 2x+4=0
2x=-4
X=-4/2
X=-2
So the answer is -2
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hi its 1
Step-by-step explanation: