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kifflom [539]
3 years ago
5

In a local basketball league championship total 198 games were played, where each team played exactly three games with all the o

ther teams. How many teams participated in this championship?
Mathematics
1 answer:
kifflom [539]3 years ago
6 0

Answer:

  12

Step-by-step explanation:

When n teams play each other once, the total number of games is n(n-1)/2. Since each team played every other one 3 times, the relationship between number of teams (n) and number of games is ...

  3(n(n-1)/2) = 198

  n(n-1) = 132 = 12·11 . . . . . . multiply by 2/3 and factor

  n = 12 . . . . . . n = -11 is also an extraneous solution to this quadratic equation

12 teams participated in this championship.

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1  10 |
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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